Prime integers below 10: 2, 3, 5, 7

Total outcomes: Number of ways you can choose 2 from 4 = \(4C2= 6 pairs\)

No. of ways for Event: Pairs that will have products greater than product of pairs not selected i.e. (3,5), (3,7), (5,7) \(= 3 pairs\)

Probability = number of ways/Total outcomes \(= 3/6 = 1/2\)

Hence choice(C) is correct.
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Thanks,

Prashant Ponde

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