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The average (arithmetic mean) of fifteen consecutive integers is 88.

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The average (arithmetic mean) of fifteen consecutive integers is 88.  [#permalink]

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New post 18 Dec 2018, 00:14
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A
B
C
D
E

Difficulty:

  15% (low)

Question Stats:

83% (01:26) correct 18% (01:55) wrong based on 44 sessions

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Concentration: Accounting, Finance
GPA: 3.68
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Re: The average (arithmetic mean) of fifteen consecutive integers is 88.  [#permalink]

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New post 18 Dec 2018, 02:40
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Bunuel wrote:
The average (arithmetic mean) of fifteen consecutive integers is 88. What is the greatest of these integers?

A. 93
B. 94
C. 95
D. 96
E. 97



The average of odd number of integers is given .

The value of 8th integer = 88. Now add 7 with that average.

88 + 7 = 95.

C is the correct answer.
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The average (arithmetic mean) of fifteen consecutive integers is 88.  [#permalink]

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New post 18 Dec 2018, 08:35
Bunuel wrote:
The average (arithmetic mean) of fifteen consecutive integers is 88. What is the greatest of these integers?

A. 93
B. 94
C. 95
D. 96
E. 97


Let the 15 numbers be -

1. a
2. ( a + 1 )
3. ( a + 2 )
...............
15. ( a + 14 )

Sum of these 15 numbers will be a*15 + ( Sum of first 14 integers )

So, \(15a + 105 = 88*15\)

Or, \(a + 7 = 88\)

Or, \(a = 81\)

So, The highest digit will be 81 + 14 = 95, Answer must be (C)
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The average (arithmetic mean) of fifteen consecutive integers is 88.   [#permalink] 18 Dec 2018, 08:35
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