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# The average (arithmetic mean) of fifteen consecutive integers is 88.

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Joined: 02 Sep 2009
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The average (arithmetic mean) of fifteen consecutive integers is 88.  [#permalink]

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18 Dec 2018, 00:14
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15% (low)

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83% (01:26) correct 18% (01:55) wrong based on 44 sessions

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The average (arithmetic mean) of fifteen consecutive integers is 88. What is the greatest of these integers?

A. 93
B. 94
C. 95
D. 96
E. 97

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Re: The average (arithmetic mean) of fifteen consecutive integers is 88.  [#permalink]

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18 Dec 2018, 02:40
1
Bunuel wrote:
The average (arithmetic mean) of fifteen consecutive integers is 88. What is the greatest of these integers?

A. 93
B. 94
C. 95
D. 96
E. 97

The average of odd number of integers is given .

The value of 8th integer = 88. Now add 7 with that average.

88 + 7 = 95.

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The average (arithmetic mean) of fifteen consecutive integers is 88.  [#permalink]

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18 Dec 2018, 08:35
Bunuel wrote:
The average (arithmetic mean) of fifteen consecutive integers is 88. What is the greatest of these integers?

A. 93
B. 94
C. 95
D. 96
E. 97

Let the 15 numbers be -

1. a
2. ( a + 1 )
3. ( a + 2 )
...............
15. ( a + 14 )

Sum of these 15 numbers will be a*15 + ( Sum of first 14 integers )

So, $$15a + 105 = 88*15$$

Or, $$a + 7 = 88$$

Or, $$a = 81$$

So, The highest digit will be 81 + 14 = 95, Answer must be (C)
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The average (arithmetic mean) of fifteen consecutive integers is 88.   [#permalink] 18 Dec 2018, 08:35
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