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# The average (arithmetic mean) of fifteen consecutive integers is 88.

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Math Expert
Joined: 02 Sep 2009
Posts: 52296
The average (arithmetic mean) of fifteen consecutive integers is 88.  [#permalink]

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17 Dec 2018, 23:14
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Difficulty:

25% (medium)

Question Stats:

75% (01:13) correct 25% (00:52) wrong based on 24 sessions

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The average (arithmetic mean) of fifteen consecutive integers is 88. What is the greatest of these integers?

A. 93
B. 94
C. 95
D. 96
E. 97

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Joined: 31 Oct 2013
Posts: 955
Concentration: Accounting, Finance
GPA: 3.68
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Re: The average (arithmetic mean) of fifteen consecutive integers is 88.  [#permalink]

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18 Dec 2018, 01:40
Bunuel wrote:
The average (arithmetic mean) of fifteen consecutive integers is 88. What is the greatest of these integers?

A. 93
B. 94
C. 95
D. 96
E. 97

The average of odd number of integers is given .

The value of 8th integer = 88. Now add 7 with that average.

88 + 7 = 95.

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The average (arithmetic mean) of fifteen consecutive integers is 88.  [#permalink]

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18 Dec 2018, 07:35
Bunuel wrote:
The average (arithmetic mean) of fifteen consecutive integers is 88. What is the greatest of these integers?

A. 93
B. 94
C. 95
D. 96
E. 97

Let the 15 numbers be -

1. a
2. ( a + 1 )
3. ( a + 2 )
...............
15. ( a + 14 )

Sum of these 15 numbers will be a*15 + ( Sum of first 14 integers )

So, $$15a + 105 = 88*15$$

Or, $$a + 7 = 88$$

Or, $$a = 81$$

So, The highest digit will be 81 + 14 = 95, Answer must be (C)
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Abhishek....

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The average (arithmetic mean) of fifteen consecutive integers is 88. &nbs [#permalink] 18 Dec 2018, 07:35
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