It is currently 12 Dec 2017, 01:41

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# The figure above shows a circular flower bed, with its center at O, su

Author Message
TAGS:

### Hide Tags

Math Expert
Joined: 02 Sep 2009
Posts: 42559

Kudos [?]: 135309 [0], given: 12686

The figure above shows a circular flower bed, with its center at O, su [#permalink]

### Show Tags

28 Nov 2017, 21:04
00:00

Difficulty:

(N/A)

Question Stats:

100% (00:39) correct 0% (00:00) wrong based on 13 sessions

### HideShow timer Statistics

The figure above shows a circular flower bed, with its center at O, surrounded by a circular path that is 3 feet wide. What is the area of the path, in square feet?

(A) 25π
(B) 38π
(C) 55π
(D) 57π
(E) 64π

[Reveal] Spoiler:
Attachment:

2017-11-28_1025.png [ 6.37 KiB | Viewed 240 times ]
[Reveal] Spoiler: OA

_________________

Kudos [?]: 135309 [0], given: 12686

BSchool Forum Moderator
Joined: 26 Feb 2016
Posts: 1691

Kudos [?]: 745 [1], given: 19

Location: India
WE: Sales (Retail)
The figure above shows a circular flower bed, with its center at O, su [#permalink]

### Show Tags

28 Nov 2017, 21:16
1
KUDOS

The outer circle has the radius of 8+3(since the circular path around the flower bed is 3 feet) = 11
Hence, the area of the outer circle is $$π*(11)^2 = 121π$$
Since the radius of the inner circle is 8, area will be $$π*(8)^2 = 64π$$

The area of the path will be the difference of area of the outer circle and the area of the inner circle.
Hence area of the path will be $$121π - 64π = 57π$$(Option D)
_________________

Stay hungry, Stay foolish

Kudos [?]: 745 [1], given: 19

Target Test Prep Representative
Status: Founder & CEO
Affiliations: Target Test Prep
Joined: 14 Oct 2015
Posts: 1922

Kudos [?]: 1011 [0], given: 3

Location: United States (CA)
Re: The figure above shows a circular flower bed, with its center at O, su [#permalink]

### Show Tags

01 Dec 2017, 07:56
Bunuel wrote:

The figure above shows a circular flower bed, with its center at O, surrounded by a circular path that is 3 feet wide. What is the area of the path, in square feet?

(A) 25π
(B) 38π
(C) 55π
(D) 57π
(E) 64π

[Reveal] Spoiler:
Attachment:
2017-11-28_1025.png

The area of the inner circle is 8^2π = 64π.

The area of the outer circle is 11^2π = 121π.

Thus, the area of the path is the difference of the two areas: 121π - 64π = 57π.

_________________

Scott Woodbury-Stewart
Founder and CEO

GMAT Quant Self-Study Course
500+ lessons 3000+ practice problems 800+ HD solutions

Kudos [?]: 1011 [0], given: 3

Intern
Joined: 26 Sep 2017
Posts: 6

Kudos [?]: 1 [0], given: 0

Re: The figure above shows a circular flower bed, with its center at O, su [#permalink]

### Show Tags

01 Dec 2017, 08:21
Area of the path = Area of larger circle (with radius 8+3=11) - Area of smaller circle (with radius 8)
=>Area of the path = π∗(11)^2 - π∗(8)^2
=>Area of the path = 121π - 64π = 57π

Kudos [?]: 1 [0], given: 0

Re: The figure above shows a circular flower bed, with its center at O, su   [#permalink] 01 Dec 2017, 08:21
Display posts from previous: Sort by