GMAT Question of the Day - Daily to your Mailbox; hard ones only

It is currently 15 Oct 2019, 11:55

Close

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Close

Request Expert Reply

Confirm Cancel

The figure above shows a circular garden plot with center O surrounded

  new topic post reply Question banks Downloads My Bookmarks Reviews Important topics  
Author Message
TAGS:

Hide Tags

Find Similar Topics 
Math Expert
User avatar
V
Joined: 02 Sep 2009
Posts: 58340
The figure above shows a circular garden plot with center O surrounded  [#permalink]

Show Tags

New post 27 Feb 2019, 23:46
00:00
A
B
C
D
E

Difficulty:

  25% (medium)

Question Stats:

79% (01:07) correct 21% (02:00) wrong based on 19 sessions

HideShow timer Statistics

Image
The figure above shows a circular garden plot with center O surrounded by a circular sidewalk, also with center O. If the area covered by the garden and sidewalk together is 169π and of the garden alone is 144π, what is the value of T ?

A. 1
B. 2
C. 3
D. 5
E. 12.5


Attachment:
2019-02-28_1044.png
2019-02-28_1044.png [ 39.53 KiB | Viewed 282 times ]

_________________
Manager
Manager
avatar
S
Joined: 17 May 2018
Posts: 140
Location: India
Re: The figure above shows a circular garden plot with center O surrounded  [#permalink]

Show Tags

New post 28 Feb 2019, 01:54
Radius of garden+ sidewalk=R
Radius of garden=r
Ar of garden= pi*r^2= 144*pi
r= 12
Ar of garden + sidewalk= pi*R^2= 169*pi
R= 13
Therefore T= R-r=13-12=1
IMO A

Posted from my mobile device
Manager
Manager
avatar
S
Joined: 17 May 2018
Posts: 140
Location: India
Re: The figure above shows a circular garden plot with center O surrounded  [#permalink]

Show Tags

New post 28 Feb 2019, 01:55
Radius of garden+ sidewalk=R
Radius of garden=r
Ar of garden= pi*r^2= 144*pi
r= 12
Ar of garden + sidewalk= pi*R^2= 169*pi
R= 13
Therefore T= R-r=13-12=1
IMO A

Posted from my mobile device
GMAT Club Legend
GMAT Club Legend
User avatar
D
Joined: 18 Aug 2017
Posts: 4999
Location: India
Concentration: Sustainability, Marketing
GPA: 4
WE: Marketing (Energy and Utilities)
GMAT ToolKit User Premium Member
Re: The figure above shows a circular garden plot with center O surrounded  [#permalink]

Show Tags

New post 28 Feb 2019, 05:59
radius of garden = 12
and radius of large circle = 13
so t= 13-12 ;1
IMO A


Bunuel wrote:
Image
The figure above shows a circular garden plot with center O surrounded by a circular sidewalk, also with center O. If the area covered by the garden and sidewalk together is 169π and of the garden alone is 144π, what is the value of T ?

A. 1
B. 2
C. 3
D. 5
E. 12.5


Attachment:
2019-02-28_1044.png
GMAT Club Bot
Re: The figure above shows a circular garden plot with center O surrounded   [#permalink] 28 Feb 2019, 05:59
Display posts from previous: Sort by

The figure above shows a circular garden plot with center O surrounded

  new topic post reply Question banks Downloads My Bookmarks Reviews Important topics  





Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne