GMAT Question of the Day - Daily to your Mailbox; hard ones only

It is currently 14 Nov 2018, 03:49

Close

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Close

Request Expert Reply

Confirm Cancel
Events & Promotions in November
PrevNext
SuMoTuWeThFrSa
28293031123
45678910
11121314151617
18192021222324
2526272829301
Open Detailed Calendar
  • $450 Tuition Credit & Official CAT Packs FREE

     November 15, 2018

     November 15, 2018

     10:00 PM MST

     11:00 PM MST

    EMPOWERgmat is giving away the complete Official GMAT Exam Pack collection worth $100 with the 3 Month Pack ($299)
  • Free GMAT Strategy Webinar

     November 17, 2018

     November 17, 2018

     07:00 AM PST

     09:00 AM PST

    Nov. 17, 7 AM PST. Aiming to score 760+? Attend this FREE session to learn how to Define your GMAT Strategy, Create your Study Plan and Master the Core Skills to excel on the GMAT.

The largest number in a series of consecutive even integers

  new topic post reply Question banks Downloads My Bookmarks Reviews Important topics  
Author Message
TAGS:

Hide Tags

Senior Manager
Senior Manager
User avatar
Joined: 21 Oct 2013
Posts: 419
The largest number in a series of consecutive even integers  [#permalink]

Show Tags

New post Updated on: 07 Feb 2014, 04:00
4
00:00
A
B
C
D
E

Difficulty:

  35% (medium)

Question Stats:

75% (01:38) correct 25% (01:26) wrong based on 234 sessions

HideShow timer Statistics

The largest number in a series of consecutive even integers is w. If the number of integers is n, what is the smallest number in terms of w and n?

A. w– 2n
B. w–n + 1
C. w– 2(n– 1)
D. n– 6 + w
E. w – n/2

OE
(A): w– 2n = 10 – 2(2) = 10 – 4 = 6 ≠ 8
(B): w–n + 1 =10 – 2 +1 = 9 ≠ 8
(C): w– 2(n– 1) = 10 – 2(2 – 1) = 10 –2 = 8 = 8
(D): n– 6 + w = 2 – 6 + 10 = 6 ≠ 8
(E): w – n/2 = 10 – 2/2 = 10 – 1 = 9 ≠ 8

Only (C) matches target number.
Conceptual approach is a bit trickier:
In a set of n consecutive integers in descending order, series would be {w, w-1, w-2, w-3…} - that is, each subsequent integer is w minus integer's position in sequence below w, or w - (n - 1).
For example, set {4, 3, 2, 1} may be written as {4, (4 -1), (4 - 2), (4 - 3)}.

Since this is a series of EVEN numbers, next smaller number in series is w - 2, and next is w - 4 - in other words, each subsequent integer subtracts 2 times number of its position below w, or w - 2(n -1).
For example, set {8, 6, 4} may be written as {8, (8 - 2(2-1), (8 - 2(3-1)}.


Hi, I want to request the solution for this question, please.

Originally posted by goodyear2013 on 06 Feb 2014, 09:46.
Last edited by Bunuel on 07 Feb 2014, 04:00, edited 1 time in total.
Edited the question.
Intern
Intern
User avatar
Joined: 15 Sep 2012
Posts: 7
Concentration: General Management
GPA: 3.48
GMAT ToolKit User
Re: The largest number in a series of consecutive even  [#permalink]

Show Tags

New post 06 Feb 2014, 10:20
2
Ciao

I would pick a random set of 3 consecutive even integers e.g. {2, 4, 6} and try all the answers choices.
IMO will be quicker.

Thanx
TC
Senior Manager
Senior Manager
User avatar
Joined: 21 Oct 2013
Posts: 419
Re: The largest number in a series of consecutive even  [#permalink]

Show Tags

New post 06 Feb 2014, 16:44
1
{2, 4, 6} --> i.e. W = 6, n = 3 to get smallest one; 2
6 - 6 = 0
6 - 3 + 1 = 4
6 - 2(2) = 2 --> Answer
3 - 6 + 6 = 3
6 - 3/2 = 4.5

Cool. Thanks!
Veritas Prep GMAT Instructor
User avatar
P
Joined: 16 Oct 2010
Posts: 8527
Location: Pune, India
Re: The largest number in a series of consecutive even  [#permalink]

Show Tags

New post 06 Feb 2014, 20:42
3
1
goodyear2013 wrote:
The largest number in a series of consecutive even integers is w. If the number of integers is n, what is the smallest number in terms of w and n?

w– 2n
w–n + 1
w– 2(n– 1)
n– 6 + w
w – n/2

OE
(A): w– 2n = 10 – 2(2) = 10 – 4 = 6 ≠ 8
(B): w–n + 1 =10 – 2 +1 = 9 ≠ 8
(C): w– 2(n– 1) = 10 – 2(2 – 1) = 10 –2 = 8 = 8
(D): n– 6 + w = 2 – 6 + 10 = 6 ≠ 8
(E): w – n/2 = 10 – 2/2 = 10 – 1 = 9 ≠ 8

Only (C) matches target number.
Conceptual approach is a bit trickier:
In a set of n consecutive integers in descending order, series would be {w, w-1, w-2, w-3…} - that is, each subsequent integer is w minus integer's position in sequence below w, or w - (n - 1).
For example, set {4, 3, 2, 1} may be written as {4, (4 -1), (4 - 2), (4 - 3)}.

Since this is a series of EVEN numbers, next smaller number in series is w - 2, and next is w - 4 - in other words, each subsequent integer subtracts 2 times number of its position below w, or w - 2(n -1).
For example, set {8, 6, 4} may be written as {8, (8 - 2(2-1), (8 - 2(3-1)}.


Hi, I want to request the solution for this question, please.



Another method would be to use the concept of Arithmetic Progressions. Consecutive even integers form an AP where the common difference is 2.
In an AP, Last term = First term + (n-1)*common difference
w = First term + (n-1)*2
First term = w - 2(n-1)

Check out this post for this concept: http://www.veritasprep.com/blog/2012/03 ... gressions/
_________________

Karishma
Veritas Prep GMAT Instructor

Learn more about how Veritas Prep can help you achieve a great GMAT score by checking out their GMAT Prep Options >

GMAT self-study has never been more personalized or more fun. Try ORION Free!

Director
Director
User avatar
S
Affiliations: CrackVerbal
Joined: 03 Oct 2013
Posts: 524
Location: India
GMAT 1: 780 Q51 V46
Re: The largest number in a series of consecutive even  [#permalink]

Show Tags

New post 06 Feb 2014, 22:03
1
[quote="goodyear2013"]The largest number in a series of consecutive even integers is w. If the number of integers is n, what is the smallest number in terms of w and n?

w– 2n
w–n + 1
w– 2(n– 1)
n– 6 + w
w – n/2

Let us say the consecutive even integers are 0, 2, 4 where w = 4, n = 3

By plugging in these values our answer should be 0

(A) 4 - 6
(B) 4 - 3 + 1
(C) 4 - 2(2)
(D) 3 - 6 + 4
(E) 4 - 3/2

Only option C satisfies that
_________________

For more info on GMAT and MBA, follow us on @AskCrackVerbal

Intern
Intern
avatar
Joined: 17 Jul 2014
Posts: 10
Location: United States
GMAT 1: 720 Q49 V38
Re: The largest number in a series of consecutive even integers  [#permalink]

Show Tags

New post 21 Jul 2014, 12:31
Since the integers are even numbers, let's assume that the first term is 2k. As the series is consecutive even integers, its 2nd term will be 2k+2, 3rd term will be 2K+4, and so on thus giving the nth term as 2k + 2(n-1).

Now,

2k+2(n-1) = w

or, 2k = w-2(n-1)
Non-Human User
User avatar
Joined: 09 Sep 2013
Posts: 8767
Premium Member
Re: The largest number in a series of consecutive even integers  [#permalink]

Show Tags

New post 29 Jul 2018, 21:02
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
_________________

GMAT Books | GMAT Club Tests | Best Prices on GMAT Courses | GMAT Mobile App | Math Resources | Verbal Resources

GMAT Club Bot
Re: The largest number in a series of consecutive even integers &nbs [#permalink] 29 Jul 2018, 21:02
Display posts from previous: Sort by

The largest number in a series of consecutive even integers

  new topic post reply Question banks Downloads My Bookmarks Reviews Important topics  


Copyright

GMAT Club MBA Forum Home| About| Terms and Conditions and Privacy Policy| GMAT Club Rules| Contact| Sitemap

Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne

Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.