mejia401 wrote:

62. The sum of three integers is 40. The largest integer is 3 times the middle integer, and the smallest integer is 23 less than the largest integer. What is the product of the three integers?

A) 1,104

B) 972

C) 672

D) 294

E) 192

Who can solve this in less than 60 seconds? And how?

Actually, from what I know of the people on this forum, many of them can solve it in under a minute.

Say middle integer is x. Largest is 3x. Smallest is 3x - 23.

3x - 23 + x + 3x = 40

x = 9

The middle integer is 9.

Now look for the option which is divisible by 9 (since the product of the 3 integers will be a multiple of 9). Sum of the digits of the number should be divisible by 9 for the number to be divisible by 9.

(B) 9+7+2 = 18 which is divisible by 9.

Only (B) works.

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