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[GMAT math practice question]

(number properties) If \(n\) is a positive integer, what is the value of \(n\)?

1) \(n(n-1)\) is a prime number

2) \(n(n+1)\) has \(4\) factors

=>

Forget conventional ways of solving math questions. For DS problems, the VA (Variable Approach) method is the quickest and easiest way to find the answer without actually solving the problem. Remember that equal numbers of variables and independent equations ensure a solution.

The first step of the VA (Variable Approach) method is to modify the original condition and the question. We then recheck the question.

Since we have \(1\) variable (\(n\)) and \(0\) equations, D is most likely to be the answer. So, we should consider each condition on its own first.

Condition 1)
Only \(n =2\) makes \(n(n-1)\) a prime number.
Thus, condition 1) is sufficient.

Condition 2)
Integers with four factors have the form \(p*q\) or \(p^3\), where \(p\) and \(q\) are prime integers.
It is impossible to have \(n(n+1)=p^3\), where \(n\) is an integer and \(p\) is a prime number.
The only time \(n(n+1) = pq\) is when \(n(n+1) = 2*3\) and \(n =2\).
Condition 2) is sufficient since it yields a unique solution.

Therefore, D is the answer.
Answer: D

If the original condition includes “1 variable”, or “2 variables and 1 equation”, or “3 variables and 2 equations” etc., one more equation is required to answer the question. If each of conditions 1) and 2) provide an additional equation, there is a 59% chance that D is the answer, a 38% chance that A or B is the answer, and a 3% chance that the answer is C or E. Thus, answer D (conditions 1) and 2), when applied separately, are sufficient to answer the question) is most likely, but there may be cases where the answer is A,B,C or E.
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[GMAT math practice question]

(function) If the symbol \(#\) represents one of addition, subtraction, multiplication, or division, what is the value of \((2 # 1)\)?

1) 2 # 2 = 1

2) (–1/2) # (-1) = \(\frac{1}{2}\)

=>

Forget conventional ways of solving math questions. For DS problems, the VA (Variable Approach) method is the quickest and easiest way to find the answer without actually solving the problem. Remember that equal numbers of variables and independent equations ensure a solution.

Since we have \(1\) variable (\(#\)) and \(0\) equations, D is most likely to be the answer. So, we should consider each condition on its own first.

Condition 1)
\(#\) is the division operation since \(\frac{2}{2} = 1.\)

So, \(2#1 = \frac{2}{1} = 2.\)

Condition 1) is sufficient since it yields a unique answer.

Condition 2)
\(#\) could be the multiplication, subtraction or the division operation
since \((-\frac{1}{2}) * (-1) = \frac{1}{2}, (-\frac{1}{2})-(-1) = (\frac{1}{2})\) and (-\(\frac{1}{2})/(-1) = \frac{1}{2}.\)

Since \(2 * 1 = 2\) and \(\frac{2}{1} = 2\), but \(2-1 = 1\), condition 2) does not yield a unique value for \(2#1\).

Condition 2) is not sufficient since it doesn’t yield a unique answer.

Therefore, A is the answer.
Answer: A

If the original condition includes “1 variable”, or “2 variables and 1 equation”, or “3 variables and 2 equations” etc., one more equation is required to answer the question. If each of conditions 1) and 2) provide an additional equation, there is a 59% chance that D is the answer, a 38% chance that A or B is the answer, and a 3% chance that the answer is C or E. Thus, answer D (conditions 1) and 2), when applied separately, are sufficient to answer the question) is most likely, but there may be cases where the answer is A,B,C or E.
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[Math Revolution GMAT math practice question]

(number property) \(n\) is an integer. Is \(n(n+2)\) a multiple of \(8\)?

1) \(n\) is an even integer
2) \(n\) is a multiple of \(4\)

=>

Forget conventional ways of solving math questions. For DS problems, the VA (Variable Approach) method is the quickest and easiest way to find the answer without actually solving the problem. Remember that equal numbers of variables and independent equations ensure a solution.

The first step of the VA (Variable Approach) method is to modify the original condition and the question. We then recheck the question.

Note that the product of two consecutive even integers is a multiple of 8 since one of them is a multiple of 4 and the other is an even integer.

Thus, each of conditions is sufficient since each implies that n and n+2 are two consecutive even integers.

Therefore, D is the answer.
Answer: D
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[Math Revolution GMAT math practice question]

(inequality) If \(x\) and \(y\) are positive, is \(1<x<y\)?

\(1) √x<x<y\)
\(2) 1<√x<y\)

=>

Forget conventional ways of solving math questions. For DS problems, the VA (Variable Approach) method is the quickest and easiest way to find the answer without actually solving the problem. Remember that equal numbers of variables and independent equations ensure a solution.

Since we have \(2\) variables (\(x\) and \(y\)) and \(0\) equations, C is most likely to be the answer. So, we should consider conditions 1) & 2) together first. After comparing the number of variables and the number of equations, we can save time by considering conditions 1) & 2) together first.

Conditions 1) & 2)
Since \(\sqrt{x}<x<y\) and \(1<\sqrt{x}<y\), we have \(1<\sqrt{x}<x<y.\) Both conditions together are sufficient.

Since this question is an inequality question (one of the key question areas), CMT (Common Mistake Type) 4(A) of the VA (Variable Approach) method tells us that we should also check answers A and B.

Condition 1)
Since \(\sqrt{x}<x,\) we have \(x > 1.\)
Thus, \(1<\sqrt{x}<x<y\) and condition 1) is sufficient.

Condition 2)
If \(x = 2\) and \(y = 3\), then the answer is ‘yes’.
If \(x = 4\) and \(y = 3\), then the answer is ‘no’
Thus, condition 2) is not sufficient, since it does not yield a unique solution.

Therefore, the correct answer is A.
Answer: A

Normally, in problems which require 2 equations, such as those in which the original conditions include 2 variables, or 3 variables and 1 equation, or 4 variables and 2 equations, each of conditions 1) and 2) provide an additional equation. In these problems, the two key possibilities are that C is the answer (with probability 70%), and E is the answer (with probability 25%). Thus, there is only a 5% chance that A, B or D is the answer. This occurs in common mistake types 3 and 4. Since C (both conditions together are sufficient) is the most likely answer, we save time by first checking whether conditions 1) and 2) are sufficient, when taken together. Obviously, there may be cases in which the answer is A, B, D or E, but if conditions 1) and 2) are NOT sufficient when taken together, the answer must be E.
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[GMAT math practice question]

(Number) What is a positive integer \(p\)?

1) \(p\) is a prime number

2) \(p^2+2\) is a prime number

=>

Forget conventional ways of solving math questions. For DS problems, the VA (Variable Approach) method is the quickest and easiest way to find the answer without actually solving the problem. Remember that equal numbers of variables and independent equations ensure a solution.
Visit https://www.mathrevolution.com/gmat/lesson for details.

Since we have \(1\) variable (\(p\)) and \(0\) equations, D is most likely to be the answer. So, we should consider each condition on its own first.

Condition 1)
Since we have an infinite number of prime numbers, we don’t have a unique value of \(p\), and condition 1) is not sufficient.

Condition 2)
If \(p\) has a remainder \(1\) when it is divided by \(3\) or \(p=3k+1\) for some integer \(k\), then \(p^2+2 = (3k+1)^2+2 = 9k^2+6k+1+2 = 3(3^k2+2k+1)\) is a multiple and it is a prime number. We have \(3k^2+2k+1=1, 3k^2+2k=0, k(3k+2)=0\) and \(k=0\) or \(k=\frac{-2}{3}\). However, \(k\) is an integer so only \(k=0\) works. Then \(p=3(0)+1 = 1\). However, \(p = 1\) is not a solution since \(1\) is not a prime number.

If \(p\) has a remainder \(2\) when it is divided by \(3\) or \(p=3k+2\) for some integer \(k\), then \(p^2+2 = (3k+2)^2+2 = 9k^2+12k+4+2 = 3(3k^2+4k+2)\) is a multiple and it is a prime number. Since we have \(3k^2+4k+2=1, 3k^2+4k+1=0\) or \((3k+1)(k+1)=0\) and we have \(k =-1\) and \(k=\frac{-1}{3}\). However, \(k\) must be an integer so then \(p=3(-1)+2 = -1.\) However, \(p = -1\) is not a solution since \(-1\) is negative.

Assume \(p\) has a remainder \(0\) when it is divided by \(3.\)
If \(p=3\), then \(p^2+2=11\) is a prime number.
If \(p=9\), then \(p^2+2=83\) is a prime number.
Since condition 2) does not yield a unique solution, it is not sufficient.

Conditions 1) & 2)
\(p\) is a multiple of \(3\) from condition 2), and \(p\) is a prime number from condition 1). Then \(p = 3.\)
Since both conditions together yield a unique solution, it is sufficient.

Therefore, C is the answer.
Answer: C

If the original condition includes “1 variable”, or “2 variables and 1 equation”, or “3 variables and 2 equations,” etc., one more equation is required to answer the question. If each of conditions 1) and 2) provide an additional equation, there is a 59% chance that D is the answer, a 38% chance that A or B is the answer, and a 3% chance that the answer is C or E. Thus, answer D (conditions 1) and 2), when applied separately, are sufficient to answer the question) is most likely, but there may be cases where the answer is A,B,C or E.
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[GMAT math practice question]

(inequalities) Which one of \(p + q\) and \(pq + 1\) greater than the other one?

1) \(-1 < p < 1. \)

2) \(-1 < q < 1.\)

=>

Forget conventional ways of solving math questions. For DS problems, the VA (Variable Approach) method is the quickest and easiest way to find the answer without actually solving the problem. Remember that equal numbers of variables and independent equations ensure a solution.
Visit https://www.mathrevolution.com/gmat/lesson for details.

The first step of the VA (Variable Approach) method is to modify the original condition and the question. We then recheck the question. We should simplify conditions if necessary.

\(pq + 1 – ( p + q )\)

\(= pq – p – q + 1\)

\(= (p-1)(q-1)\)

The question asks if \((p-1)(q-1)\) is positive or negative.

If we have \(p>1, q>1\) or \(p<1, q<1\), then \((p-1)(q-1)\) is positive.

Thus, both conditions together are sufficient, since they tell \(p < 1\) and \(q < 1.\)

Therefore, C is the answer.
Answer: C
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[GMAT math practice question]

(Number Properties) \(m\) and \(n\) are positive integers. What is the value of \(mn\)?

1) \(2.03(\frac{n}{m}) = (0.3)^2 \)

2) \(m\) and \(n\) are relatively prime integers.

=>

Forget conventional ways of solving math questions. For DS problems, the VA (Variable Approach) method is the quickest and easiest way to find the answer without actually solving the problem. Remember that equal numbers of variables and independent equations ensure a solution.
Visit https://www.mathrevolution.com/gmat/lesson for details.

Since we have \(2\) variables (\(m\) and \(n\)) and \(0\) equations, C is most likely the answer. So, we should consider conditions 1) & 2) together first. After comparing the number of variables and the number of equations, we can save time by considering conditions 1) & 2) together first.

Conditions 1) & 2) together tell us that \(m\) and \(n\) are relatively prime integers with \(203n = 9m.\)

We have \(\frac{203}{100}*\frac{n}{m}=(\frac{3}{10})^2=\frac{9}{100}\) or \(203n = 9m\) from condition 1).

Since \(m\) and \(n\) are relatively prime, we have \(m = 203\) and \(n = 9.\)

The answer is unique, and conditions 1) and 2) together are sufficient according to Common Mistake Type 2, which states that the number of answers must be only one.

Since this question is an integer question (one of the key question areas), CMT (Common Mistake Type) 4(A) of the VA (Variable Approach) method tells us that we should also check answers A and B.

Let’s look at condition 1). It tells us that \(203n = 9m.\)

If \(m = 203\) and \(n = 9\), then we have \(mn = 1827.\)

If \(m = 406\) and \(n = 18\), then we have \(mn = 7308.\)

The answer is not unique, and the condition is not sufficient, according to Common Mistake Type 2, which states that the number of answers must be only one.

Let’s look at condition 2). It tells us that \(m\) and \(n\) are relative primes.

If \(m = 203\) and \(n = 9\), then we have \(mn = 1827.\)

If \(m = 2\) and \(n = 3\), then we have \(mn = 6.\)

The answer is not unique, and the condition is not sufficient, according to Common Mistake Type 2, which states that the number of answers must be only one.

Both conditions 1) & 2) together are sufficient.

Therefore, C is the correct answer.
Answer: C

Normally, in problems which require 2 equations, such as those in which the original conditions include 2 variables, or 3 variables and 1 equation, or 4 variables and 2 equations, each of conditions 1) and 2) provide an additional equation. In these problems, the two key possibilities are that C is the answer (with probability 70%), and E is the answer (with probability 25%). Thus, there is only a 5% chance that A, B, or D is the answer. This occurs in Common Mistake Types 3 and 4. Since C (both conditions together are sufficient) is the most likely answer, we save time by first checking whether conditions 1) and 2) are sufficient, when taken together. Obviously, there may be cases in which the answer is A, B, D, or E, but if conditions 1) and 2) are NOT sufficient when taken together, the answer must be E.
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[GMAT math practice question]

(propotional) What is \(\frac{z^2}{xy} + \frac{x^2}{yz} + \frac{y^2}{zx}\) ?

\(1) x:y = 2:3\)

\(2) x:z = 1:2\)

=>

Forget conventional ways of solving math questions. For DS problems, the VA (Variable Approach) method is the quickest and easiest way to find the answer without actually solving the problem. Remember that equal numbers of variables and independent equations ensure a solution.
Visit https://www.mathrevolution.com/gmat/lesson for details.

Since we have \(3\) variables (\(x, y\), and \(z\)) and \(0\) equations, E is most likely the answer. So, we should consider conditions 1) & 2) together first. After comparing the number of variables and the number of equations, we can save time by considering conditions 1) & 2) together first.

Conditions 1) & 2)
Since \(x:y = 2:3\) and \(x:z = 1:2\), we have \(x:y:z = 2:3:4.\)

Then we have \(x = 2k, y = 3k\), and \(z = 4k\) for some number \(k.\)

\(\frac{z^2}{xy} + \frac{x^2}{yz} + \frac{y^2}{zx}\)

\(= \frac{(4k)^2}{(2k)(3k)} + \frac{(2k)^2}{(3k)(4k)} + \frac{(3k)^2}{(4k)(2k)}\)

\(= \frac{16k^2}{6k^2} + \frac{4k^2}{12k^2} + \frac{9k^2}{8k^2}\)

\(= \frac{16}{6} + \frac{4}{12} + \frac{9}{8}\)

\(= \frac{64}{24} + \frac{8}{24} + \frac{27}{24} = \frac{99}{24} = \frac{33}{8}.\)

Since both conditions together yield a unique solution, they are sufficient.

Therefore, C is the answer.
Answer: C

In cases where 3 or more additional equations are required, such as for original conditions with “3 variables”, or “4 variables and 1 equation”, or “5 variables and 2 equations”, conditions 1) and 2) usually supply only one additional equation. Therefore, there is an 80% chance that E is the answer, a 15% chance that C is the answer, and a 5% chance that the answer is A, B or D. Since E (i.e. conditions 1) & 2) are NOT sufficient, when taken together) is most likely to be the answer, it is generally most efficient to begin by checking the sufficiency of conditions 1) and 2), when taken together. Obviously, there may be occasions on which the answer is A, B, C or D.
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Hey thanks for the super helpful reply. I'm not sure how I missed that thread.
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[GMAT math practice question]

(absolute value) Is \(x<y<z\) ?

\(1) |x+1|<y<z+1\)
\(2) |x-1|<y<z-1\)

=>

Forget conventional ways of solving math questions. For DS problems, the VA (Variable Approach) method is the quickest and easiest way to find the answer without actually solving the problem. Remember that equal numbers of variables and independent equations ensure a solution.

Since we have \(3\) variables (\(x, y\) and \(z\)) and \(0\) equations, E is most likely to be the answer. So, we should consider conditions 1) & 2) together first. After comparing the number of variables and the number of equations, we can save time by considering conditions 1) & 2) together first.

Conditions 1) & 2)
By condition 1), \(x < y\) since \(x < x + 1 ≤ | x + 1 | < y\).
By condition 2), \(y < z\) since \(y < z – 1 < z.\)
Therefore, \(x < y < z\).
Thus, both conditions 1) & 2) together are sufficient.

Since this question is an absolute value question (one of the key question areas), CMT (Common Mistake Type) 4(A) of the VA (Variable Approach) method tells us that we should also check answers A and B.

Condition 1)
If \(x = 1, y = 3\), and \(z = 5,\) then the answer is ‘yes’.
If \(x = 1, y = 3,\) and \(z = 2.9\), then the answer is ‘no’ since z < y.
Thus, condition 1) is not sufficient, since it does not yield a unique solution.

Condition 2)
If \(x = 1, y = 3,\) and \(z = 5\), then the answer is ‘yes’.
If \(x = 3.1, y = 3,\) and \(z = 5\), then the answer is ‘no’ since \(x > y\).
Thus, condition 2) is not sufficient, since it does not yield a unique solution.

Therefore, C is the answer.
Answer: C

In cases where 3 or more additional equations are required, such as for original conditions with “3 variables”, or “4 variables and 1 equation”, or “5 variables and 2 equations”, conditions 1) and 2) usually supply only one additional equation. Therefore, there is an 80% chance that E is the answer, a 15% chance that C is the answer, and a 5% chance that the answer is A, B or D. Since E (i.e. conditions 1) & 2) are NOT sufficient, when taken together) is most likely to be the answer, it is generally most efficient to begin by checking the sufficiency of conditions 1) and 2), when taken together. Obviously, there may be occasions on which the answer is A, B, C or D.
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[GMAT math practice question]

(number properties) \(x\) is a positive even integer, and \(y\) is a number. Which one of \(\frac{1}{2} ⅹ \frac{3}{4} ⅹ \frac{5}{6} ⅹ…..ⅹ \frac{x-1}{x}\) and \(\frac{1}{y}\) is greater?

1) \(x = y^2.\)

2) \(y\) is positive.

=>

Forget conventional ways of solving math questions. For DS problems, the VA (Variable Approach) method is the quickest and easiest way to find the answer without actually solving the problem. Remember that equal numbers of variables and independent equations ensure a solution.
Visit https://www.mathrevolution.com/gmat/lesson for details.

The first step of the VA (Variable Approach) method is to modify the original condition and the question. We then recheck the question. We should simplify conditions if necessary.

We have \(\frac{1}{2} < \frac{2}{3}, \frac{3}{4} < \frac{4}{5}, …, \frac{99}{100} < \frac{100}{101}, … , \frac{(x-1)}{x} < \frac{x}{(x+1)}.\)

Assume \(S\) is the multiple of the left-hand sides, \((\frac{1}{2})(\frac{3}{4})…\frac{(x-1)}{x}\) and \(T\) is the multiple of the right-hand sides, \((\frac{2}{3})(\frac{4}{5})…(\frac{x}{(x+1)})\).

Then, we have \(S^2 < ST = (\frac{1}{2})(\frac{2}{3})…(\frac{(x-1)}{x})(\frac{x}{(x+1)}) = \frac{1}{(x+1)}\) or \(S < (\frac{1}{2})(\frac{3}{4})…(\frac{x}{(x+1)}) < \frac{1}{ √(x+1)}\)

Since we have \(2\) variables (\(x\) and \(y\)) and \(0\) equations, C is most likely the answer. So, we should consider conditions 1) & 2) together first. After comparing the number of variables and the number of equations, we can save time by considering conditions 1) & 2) together first.

Conditions 1) & 2)
\(S < \frac{1}{ √(x+1)} < \frac{1}{√x} = \frac{1}{y}\) since \(y = √x\) because \(y > 0\) and \(x = y^2\) so \(y = √x.\)

Then we have \(\frac{1}{2} ⅹ \frac{3}{4} ⅹ \frac{5}{6} ⅹ…..ⅹ \frac{x-1}{x} < \frac{1}{y}.\)
Since both conditions together yield a unique solution, they are sufficient.

Therefore, C is the answer.
Answer: C

Normally, in problems which require 2 equations, such as those in which the original conditions include 2 variables, or 3 variables and 1 equation, or 4 variables and 2 equations, each of conditions 1) and 2) provide an additional equation. In these problems, the two key possibilities are that C is the answer (with probability 70%), and E is the answer (with probability 25%). Thus, there is only a 5% chance that A, B, or D is the answer. This occurs in common mistake types 3 and 4. Since C (both conditions together are sufficient) is the most likely answer, we save time by first checking whether conditions 1) and 2) are sufficient, when taken together. Obviously, there may be cases in which the answer is A, B, D, or E, but if conditions 1) and 2) are NOT sufficient when taken together, the answer must be E.
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[GMAT math practice question]

(Number Properties) \(a, b, \)and \(c\) are \(3\) different unit numbers. What is the \(3\)-digit number \(abc\)?

1) The \(5\)-digit number \(ababc\) is a multiple of \(12\).

2) The \(2\)-digit number \(ab\) is equal to \(c^2\).

=>

Forget conventional ways of solving math questions. For DS problems, the VA (Variable Approach) method is the quickest and easiest way to find the answer without actually solving the problem. Remember that equal numbers of variables and independent equations ensure a solution.
Visit https://www.mathrevolution.com/gmat/lesson for details.

Since we have \(3\) variables (\(a, b\), and \(c\)) and \(0\) equations, E is most likely the answer. So, we should consider conditions 1) & 2) together first. After comparing the number of variables and the number of equations, we can save time by considering conditions 1) & 2) together first.

Conditions 1) & 2)

Since the \(5\)-digit number \(ababc\) is a multiple of \(12\), it is a multiple of both \(3\) and \(4\). It means we have \(a + b + a + b + c = 2a + 2b + c\), which is a multiple of \(3\), and \(10b + c\) is a multiple of \(4\) since we can check the multiplicity of \(3\) with the sum of all digits and the multiplicity of \(4\) with the last two digits.

Since the \(2\)-digit number ab is equal to \(c^2\), we have \(10a + b = c^2.\)

Then, the possible solutions of (\(a, b, c\)) are (\(1, 6, 4\)), (\(4, 9, 7\)), (\(6, 4, 8\)), (\(8, 1, 9\)) from condition 2) since \(a, b\), and \(c\) are different and \(a\) is not equal to \(0\).

When we apply condition 1), we get \(a = 1, b = 6\) and \(c = 4. \) This is because \(a + b + a + b + c\) = multiple of \(3\), and in this case \(1 + 6 + 1 + 6 + 4 = 18\), which is a multiple of \(3\).

Since both conditions together yield a unique solution, they are sufficient.

Since this question is an integer question (one of the key question areas), CMT (Common Mistake Type) 4(A) of the VA (Variable Approach) method tells us that we should also check answers A and B.

Condition 1)
\(a = 1, b = 3, c = 2\) and \(a = 7, b = 3, c = 2\) are possible solutions.

Since condition 1) does not yield a unique solution, it is not sufficient.

Condition 2)
\(A = 1, b = 6, c = 4\). and \(a = 4, b = 9, c = 7\) are possible solutions from the above reasoning.

Since condition 2) does not yield a unique solution, it is not sufficient.

Therefore, C is the answer.
Answer: C

In cases where 3 or more additional equations are required, such as for original conditions with “3 variables”, or “4 variables and 1 equation”, or “5 variables and 2 equations”, conditions 1) and 2) usually supply only one additional equation. Therefore, there is an 80% chance that E is the answer, a 15% chance that C is the answer, and a 5% chance that the answer is A, B or D. Since E (i.e. conditions 1) & 2) are NOT sufficient, when taken together) is most likely to be the answer, it is generally most efficient to begin by checking the sufficiency of conditions 1) and 2), when taken together. Obviously, there may be occasions on which the answer is A, B, C, or D.
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[GMAT math practice question]

(absolute value) \(3x+4y=?\)

\(1) 2|x|+3|y|=0\)
\(2) 3|x|+2|y|=0\)

=>
Forget conventional ways of solving math questions. For DS problems, the VA (Variable Approach) method is the quickest and easiest way to find the answer without actually solving the problem. Remember that equal numbers of variables and independent equations ensure a solution.

The first step of the VA (Variable Approach) method is to modify the original condition and the question. We then recheck the question.

Condition 1)
Since \(|x| ≥ 0, |y| ≥ 0\) and \(2|x| + 3|y| = 0,\) we have \(x = y = 0.\)
Therefore, \(3x + 4y = 0.\)
Condition 1) is sufficient.

Condition 2)
Since \(|x| ≥ 0, |y| ≥ 0\) and \(3|x| + 2|y| = 0\), we have \(x = y = 0.\)
Therefore, \(3x + 4y = 0\). Condition 2) is sufficient.

FYI: Tip 1) of the VA method states that D is most likely to be the answer if conditions 1) and 2) provide the same information.

Therefore, the answer is D.
Answer: D
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[GMAT math practice question]

(number properties) \(m\) and \(n\) are positive integers greater than \(6\). What is the value of \(m + n\)?

\(1) m*n = 504\)

\(2) m\) and \(n\) are multiples of \(6\)

=>

Forget conventional ways of solving math questions. For DS problems, the VA (Variable Approach) method is the quickest and easiest way to find the answer without actually solving the problem. Remember that equal numbers of variables and independent equations ensure a solution.

Since we have \(2\) variables (\(m\) and \(n\)) and \(0\) equations, C is most likely to be the answer. So, we should consider conditions 1) & 2) together first. After comparing the number of variables and the number of equations, we can save time by considering conditions 1) & 2) together first.

Conditions 1) & 2)
Condition 1) allows us to write \(m = 6a\) and \(n = 6b\), where \(a\) and \(b\) are integers greater than \(1\).
So, \(m*n = 6a*6b = 36*a*b = 504\).
This yields \(ab = 14\). So, \(a = 2\) and \(b = 7\) or \(a = 7\) and \(b = 2\).
Thus, \(m=12\) and \(n=42\) or \(m=42\) and \(n=12\), and we obtain the unique answer \(m+n = 54\).
Both conditions together are sufficient.

Since this question is an integer question (one of the key question areas), CMT (Common Mistake Type) 4(A) of the VA (Variable Approach) method tells us that we should also check answers A and B.

Condition 1)
\(m*n = 504 = 2^3*3^2*7\)
If \(m = 12\) and \(n = 42\), then \(m + n = 54.\)
If \(m = 8\) and \(n = 63\), then \(m + n = 71\).
Condition 1) is not sufficient since it does not yield a unique answer.

Condition 2)
If \(m = 12\) and \(n = 12\), then \(m + n = 24\).
If \(m = 12\) and \(n = 24\), then \(m + n = 36\).
Condition 2) is not sufficient since it does not yield a unique answer.

Therefore, C is the answer.
Answer: C

Normally, in problems which require 2 equations, such as those in which the original conditions include 2 variables, or 3 variables and 1 equation, or 4 variables and 2 equations, each of conditions 1) and 2) provide an additional equation. In these problems, the two key possibilities are that C is the answer (with probability 70%), and E is the answer (with probability 25%). Thus, there is only a 5% chance that A, B or D is the answer. This occurs in common mistake types 3 and 4. Since C (both conditions together are sufficient) is the most likely answer, we save time by first checking whether conditions 1) and 2) are sufficient, when taken together. Obviously, there may be cases in which the answer is A, B, D or E, but if conditions 1) and 2) are NOT sufficient when taken together, the answer must be E.
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[GMAT math practice question]

(Algebra) \(x\) and \(y\) are real numbers. What is the value of \(x + y\)?

1) \(\frac{x}{y} = -\sqrt{3}\)

2) \(x + \sqrt{3}y = 0\)

=>

Forget conventional ways of solving math questions. For DS problems, the VA (Variable Approach) method is the quickest and easiest way to find the answer without actually solving the problem. Remember that equal numbers of variables and independent equations ensure a solution.
Visit https://www.mathrevolution.com/gmat/lesson for details.

Since we have \(2\) variables (\(x\) and \(y\)) and \(0\) equations, C is most likely the answer. So, we should consider conditions 1) & 2) together first. After comparing the number of variables and the number of equations, we can save time by considering conditions 1) & 2) together first.

Conditions 1) & 2)

If \(x = -√3, y = 1,\) then we have \(x + y = -√3 + 1.\)

If \(x = √3, y = -1,\) then we have \(x + y = √3 - 1.\)

Since both conditions together do not yield a unique solution, they are not sufficient.

Note: Tip 1) of the VA method states that D is 95% likely to be the answer if condition 1) gives the same information as condition 2). However, we have the answer E in this problem.

Therefore, E is the answer.
Answer: E

Normally, in problems which require 2 equations, such as those in which the original conditions include 2 variables, or 3 variables and 1 equation, or 4 variables and 2 equations, each of conditions 1) and 2) provide an additional equation. In these problems, the two key possibilities are that C is the answer (with probability 70%), and E is the answer (with probability 25%). Thus, there is only a 5% chance that A, B, or D is the answer. This occurs in common mistake types 3 and 4. Since C (both conditions together are sufficient) is the most likely answer, we save time by first checking whether conditions 1) and 2) are sufficient, when taken together. Obviously, there may be cases in which the answer is A, B, D, or E, but if conditions 1) and 2) are NOT sufficient when taken together, the answer must be E.
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[GMAT math practice question]

(number properties) \(n\) is a positive integer. What is the value of \(n\)?

1) \(n\) is less than \(200\)

2) the number of positive factors of \(n\) is \(15\)

=>

Forget conventional ways of solving math questions. For DS problems, the VA (Variable Approach) method is the quickest and easiest way to find the answer without actually solving the problem. Remember that equal numbers of variables and independent equations ensure a solution.

Since we have \(1\) variable (\(n\)) and \(0\) equations, D is most likely to be the answer. So, we should consider each condition on its own first.
Condition 1) is obviously not sufficient.

Condition 2)
If \(n\) has \(15\) factors, then \(n = p^4*q^2\) or \(n=p^{14}\), where \(p\) and \(q\) are prime numbers.
Condition 2) is not sufficient, since there are a lot of possibilities.

Conditions 1) & 2)
If \(p = 2\) and \(q = 3\) and \(n = p^4*q^2\), then \(n = (2^4)(3^2) = 144\). Note that \(2^14 = 16384 > 200\) and \(3^4 2^2 = 324 > 200\), so this is the only possible value of \(n\) satisfying conditions 1) and 2). For example, if \(p = 2\) and \(q = 5\), then \(n = 400.\)

Therefore, C is the answer.
Answer: C

If the original condition includes “1 variable”, or “2 variables and 1 equation”, or “3 variables and 2 equations” etc., one more equation is required to answer the question. If each of conditions 1) and 2) provide an additional equation, there is a 59% chance that D is the answer, a 38% chance that A or B is the answer, and a 3% chance that the answer is C or E. Thus, answer D (conditions 1) and 2), when applied separately, are sufficient to answer the question) is most likely, but there may be cases where the answer is A,B,C or E.
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[GMAT math practice question]

(algebra) What is the value of \(\frac{(a-b)}{(a+b)} –ab + \frac{b}{c}\) ?

\(1) a=bc\)

\(2) a=\frac{1}{2}\)

=>

Forget conventional ways of solving math questions. For DS problems, the VA (Variable Approach) method is the quickest and easiest way to find the answer without actually solving the problem. Remember that equal numbers of variables and independent equations ensure a solution.

Since we have \(3\) variables (\(x, y\) and \(z\)) and \(0\) equations, E is most likely to be the answer. So, we should consider conditions 1) & 2) together first. After comparing the number of variables and the number of equations, we can save time by considering conditions 1) & 2) together first.

Conditions 1) & 2)
Plugging in \(a = bc = \frac{1}{2}\) yields

\(\frac{(a-b)}{(a+b)} – ab + \frac{b}{c} = \frac{(bc-b)}{(bc+b)} – b^2c + \frac{b}{c} = \frac{b(c-1)}{b(c+1)} – (\frac{1}{2})c + \frac{(bc)}{c^2} = \frac{(c-1)}{(c+1)} – \frac{1}{2c} + \frac{1}{(2c^2)}.\)

Since we don’t know the value of \(c\), both conditions together don’t yield a unique solution and they are not sufficient.

Therefore, E is the answer.
Answer: E

In cases where 3 or more additional equations are required, such as for original conditions with “3 variables”, or “4 variables and 1 equation”, or “5 variables and 2 equations”, conditions 1) and 2) usually supply only one additional equation. Therefore, there is an 80% chance that E is the answer, a 15% chance that C is the answer, and a 5% chance that the answer is A, B or D. Since E (i.e. conditions 1) & 2) are NOT sufficient, when taken together) is most likely to be the answer, it is generally most efficient to begin by checking the sufficiency of conditions 1) and 2), when taken together. Obviously, there may be occasions on which the answer is A, B, C or D.
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