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Bunuel
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Greetings!
I will appreciate if someone could provide an easier and faster method to solve.


Posted from my mobile device
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File comment: Solved the question, but the approach is not fast enough.
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PRamesh2008
This is another way of solving the Problem..

Hope it helps..!!
the 2nd part need not be done -

the area = 1/2*b*h = 1/2*(distance between p & q = 2c =20)*(draw a perpendicular from A to y-axis= h = 6) = 60
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The y-intercepts, P and Q, of two perpendicular lines intersecting at the point A(6, 8) have a sum of zero. What is the area of triangle APQ ?

(A) 45
(B) 48
(C) 54
(D) 60
(E) 72

Let A(6,8) alongwith P (0,y) and Q (0,-y) form a right angled triangle APQ.

Perpendicular from A on y-axis say, R (with coordinates as (0,8))

Then triangle PRA and ARP are similar.

Hence, PR/RA = AR/RP
(y-8)/6= 6/(8-(-y))
(y-8)/6= 6/(8+y)

Solving, we get y =10

Therefore, Area of the Triangle = 1/2 * Base * Height
= 1/2 * (10 - (-10)) * 6
= 1/2 * 20 * 6
= 60


Correct option is Option D
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