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04 Jul 2024, 01:30
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D
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There are 450 boxes to load on a truck. A and B working independently but at the same time take 30 minutes to load the truck. How long should it take B working by himself to load the truck?
(1) A loads twice as many boxes as B
(2) A would take 45 minutes by himself.
(1) A loads twice as many boxes as B
(2) A would take 45 minutes by himself.
04 Jul 2024, 02:04
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I think D,
There are 450 boxes to load on a truck. A and B working independently but at the same time take 30 minutes to load the truck.
Assuming their efficiency to load truck A boxes/min and B boxes/min,
Therefore, 30*(A+B) = 450
A+B = 15--Eq1
How long should it take B working by himself to load the truck?
1st - A loads twice as many boxes as B
A=2B Substituting in eq1 3B = 15
B=5
Time taken by B load truck = 450 / 5 = 90mins Sufficient.
2nd - A would take 45 minutes by himself.
A efficiency = 450 / 45 = 10
Therfore B = 5 from eq1
Time taken by B load truck = 450 / 5 = 90mins Sufficient.
There are 450 boxes to load on a truck. A and B working independently but at the same time take 30 minutes to load the truck.
Assuming their efficiency to load truck A boxes/min and B boxes/min,
Therefore, 30*(A+B) = 450
A+B = 15--Eq1
How long should it take B working by himself to load the truck?
1st - A loads twice as many boxes as B
A=2B Substituting in eq1 3B = 15
B=5
Time taken by B load truck = 450 / 5 = 90mins Sufficient.
2nd - A would take 45 minutes by himself.
A efficiency = 450 / 45 = 10
Therfore B = 5 from eq1
Time taken by B load truck = 450 / 5 = 90mins Sufficient.
04 Jul 2024, 04:30
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Combined rate to load 450 boxes is 30 minutes
\(\frac{1}{A} + \frac{1}{B} = \frac{1}{30}\)
Rate of B?
Statement 1: A loads twice as many boxes as B
Rate of A is half as rate of B
\(\frac{1}{A} = \frac{2}{B}\)
\(\frac{2}{B} + \frac{1}{B} = \frac{1}{30}\)
SUFFICIENT
Statement 2: A would take 45 minutes by himself
Rate of A is \(\frac{1}{45}\)
\(\frac{1}{45} + \frac{1}{B} = \frac{1}{30}\)
SUFFICIENT
Answer is D
\(\frac{1}{A} + \frac{1}{B} = \frac{1}{30}\)
Rate of B?
Statement 1: A loads twice as many boxes as B
Rate of A is half as rate of B
\(\frac{1}{A} = \frac{2}{B}\)
\(\frac{2}{B} + \frac{1}{B} = \frac{1}{30}\)
SUFFICIENT
Statement 2: A would take 45 minutes by himself
Rate of A is \(\frac{1}{45}\)
\(\frac{1}{45} + \frac{1}{B} = \frac{1}{30}\)
SUFFICIENT
Answer is D
