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Originally posted by HunterJ on 01 Nov 2015, 20:10.
Last edited by HunterJ on 02 Nov 2015, 12:06, edited 2 times in total.
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Three hoses work to fill a tub at at different rate. Hose A and B, working together, can fill the tub in 6/5 of an hour. Hoses A and C can fill it in 3/2 an hour. Houses B and C can fill it in 2 hours. How long does it take all 3 hoses, working together, to fill the tub?
A. 3/10
B. 2/5
C. 1/2
D. 1
E. 6/5
Edited for accurate solution
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Three hoses work to fill a tub at at different rate. Hose A and B, working together, can fill the tub in 6/5 of an hour. Hoses A and C can fill it in 3/2 an hour. Houses B and C can fill it in 2 hours. How long does it take all 3 hoses, working together, to fill the tub?
A. 3/10
B. 2/5
C. 1/2
D. 2/3
E. 6/5
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Convert the given time to rate and you will be able to add it up.
Total Rate of A and B = Rate of A + Rate of B = 1/(6/5) = 5/6 Total Rate of A and C = Rate of A + Rate of C = 1/(3/2) = 2/3 Total Rate of B and C = Rate of B + Rate of C = 1/2
Adding all three, 2(Rate of A + Rate of B + Rate of C) = 5/6 + 2/3 + 1/2 = 2 Rate of A + Rate of B + Rate of C = 1 tub/hour
Time taken by all three together to fill up the tub is 1 hour.
Three hoses work to fill a tub at at different rate. Hose A and B, working together, can fill the tub in 6/5 of an hour. Hoses A and C can fill it in 3/2 an hour. Houses B and C can fill it in 2 hours. How long does it take all 3 hoses, working together, to fill the tub?
A. 3/10
B. 2/5
C. 1/2
D. 1
E. 6/5
Edited for accurate solution
Show more
We have ,in 1 hour when two hose working together can fill the tub as follow: 1/a + 1/b = 1/6/5 of the work 1/a + 1/c = 1/3/2 of the work 1/b + 1/c = 1/2 of the work =>Get total both sides we got : 2(1/a +1/b +1/c) = 12/6 of the work or 1/a +1/b +1/c = 6/6=1 of the work Calculate total amount of time taken when three hoses work together 1/1 = 1
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