The bar graph shows the home regions of all attendees of the Cowboy

Question

https://gmatclub.com/gmat-focus-tests/resources/import/img/I14-24.png The bar graph shows the home regions of all attendees of the Cowboy Poetry Gathering, which was held twice: in 1989 and 1992, in Elko. The color combinations in the graph represent the attendees' home regions for both years. All attendees from the 1989 gathering also attended the 1992 gathering. The pie chart shows how each of the 571 attendees ( n ) of the 1992 gathering learned about the event, with all of them providing responses to the survey. Select from each drop-down menu the option that creates the most accurate statement, given the information provided. The number of attendees who were invited to attend 1992 gathering was closest to GRAPH_1_PLACEHOLDER . If the number of attendees from Montana remained exactly the same in both the 1989 and 1992 gatherings, GRAPH_2_PLACEHOLDER of the 13 given regions had more attendees in 1992 compared to 1989. I14-24a.png

Bunuel · Answer

Official Solution:

Drop-down 1: 
 
From the pie chart, 1% of the 571 attendees were invited, which corresponds to approximately 6 people.
 
 Drop-down 2: 
 
From the pie chart, attendees from 1989 accounted for 25% of the 1992 attendees, indicating that the number of attendees in 1992 was four times that of 1989. For a region to have had more attendees in 1989 than in 1992, the bar for 1989 would need to be more than four times the bar for 1992. We are told that, for Montana, the number of attendees remained unchanged, meaning the bar for 1989 is exactly four times the bar for 1992. No other region has a bar that is more than four times larger in 1989 than in 1992, so 12 out of the 13 regions (excluding Montana) had more attendees in 1992 than in 1989.

Correct answer:

Dropdown 1:  "6"

Dropdown 2:  "12"

Adit_ · Answer

After getting millions wrong in these graph problems, finally got one right in time properly..

pappal · Answer

for 1: its 1% of 571=5.7~ 6 
now for 2: its given no. of attendees in 89 = no. of attendees in 92 (for Montana)
in other words 6% of no. of attendees in 89 = 1% of no. of attendees in 92
 i.e. 1% of no. of attendees in 89= 1/6% of no. of attendees in 92 or 18% of no. of attendees in 89 = 3% of no. of attendees in 92 or so on.
now we have to look for the graph of 92 which follows the similar above %age relationship.
It could be easy to deduce by just looking that only Montana has the relation in which numbers in both years is same, otherwise in all other cases no. in 92 is larger than in 89.  so 12

The bar graph shows the home regions of all attendees of the Cowboy

Prep Toolkit

Top 5 GMAT Debrief Videos

615 to 715 in 15 Days (Ria's Strategies)

More than Quant/Verbal Abilities: Speed vs. Accuracy

745 with Only Self-Prep and GMAT Club

From 555 to 765: 210-point Improvement

Perfect 805 Score Debrief by Julia

My Rewards

GMAT Graphs and Tables (G&T) Questions

The bar graph shows the home regions of all attendees of the Cowboy

Prep Toolkit

615 to 715 in 15 Days (Ria's Strategies)

More than Quant/Verbal Abilities: Speed vs. Accuracy

745 with Only Self-Prep and GMAT Club

From 555 to 765: 210-point Improvement

Perfect 805 Score Debrief by Julia

My Rewards