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jamifahad
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since total cashed checks = 7 ans $10 check cashed = one less or more than $50 checks
Therefore either $10 checks = 3 and $50 checks = 4 OR $10 checks = 4 and $50 checks = 3

using this information 1st option gives us the maximum cashed value therefore if we negate this value from total value we will get minimum value of which checks have lost

Therfore 1500 - 230 = 1270 hence answer is D
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Thank you guys. Guess i got confused with wordings.
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jamifahad
Thank you guys. Guess i got confused with wordings.

Its more of a trick question than anything else. To tackle such stuff, It will he helpful to read the question probably again and then make a note on the work sheet on what exactly is needed. In this,m "Minimum loss" or "Find least loss outcome?" etc , just a remainder for you to check before submitting an answer.
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Thank you guys. Guess i got confused with wordings.

For such kind of questions, i always write stuff down.
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10 x + 15 y = 1500
50 and 10 denominations can be either 4 and 3 or 3 and 4
to minimise the lost money, we have to maximize the money used

so 4 - 50$ and 3 10$ are used which equates to 230

subtracting 230 from 1500 = 1270 answer
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I do not understand this question why ? I am non native . could anyone explain what is meaning ?
why we say= "To MINIMIZE the value of the LOST checks, we must MAXIMIZE the value of the CASHED checks. "
I go for B but is not true !
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jamifahad
A tourist purchased a total of $1,500 worth of traveler’s checks in $10 and $50 denominations. During the trip the tourist cashed 7 checks and then lost all of the rest. If the number of $10 checks cashed was one more or one less than the number of $50 checks cashed, what is the minimum possible value of the checks that were lost?

(A) $1,430
(B) $1,310
(C) $1,290
(D) $1,270
(E) $1,150

The tourist cashed 7 checks. The number of $10 checks cashed was one more OR one less than the number of $50 checks cashed
There are two possible cases:
case i: The tourist cashed 4 10-dollar checks and 3 50-dollar checks
case ii: The tourist cashed 3 10-dollar checks and 4 50-dollar checks

What is the minimum possible value of the checks that were lost?
To minimize the value of the lost checks, we must MAXIMIZE the value of the checks that were cashed.

Case ii (above) maximizes the value of the checks that were cashed.
Value of 3 10-dollar checks and 4 50-dollar checks = (3)($10) + (4)($50) = $230

Value of checks that were LOST = $1,500 - $230 = $1270

Answer: D
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Don't get scared after reading the question... It's very basic :)

To get the minimum value of checks lost

you just have to maximize the value of the 7 cashed checks.

You have 7 checks that are cashed

and...

The number of $10 checks cashed was one more OR one less than the number of $50 checks cashed

Hence...

3($10) + 4($50) = $230

$1500 - $230 = $1270
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