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Paradox69
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We need to find What is the probability that the sum of two dice will yield a 4 or a 6?

As we are rolling two dice => Number of cases = \(6^2\) = 36

Now for the sum to be 4 or 6 we need to find out what comes in both the dice roll. Following outcomes will yield 4 or 6 as the sum
(1,3), (1,5), (2,2), (2,4), (3,1), (3,3), (4,2), (5,1) = 8 outcomes

=> Probability that the sum of two dice will yield a 4 or a 6 = \(\frac{8}{36}\) = \(\frac{2}{9}\)

So, Answer will be \(\frac{2}{9}\)
Hope it helps!

Watch the following video to learn How to Solve Dice Rolling Probability Problems

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Short hand trick for two dice questions-

Total events: 6 x 6 = 36

In case of sum of any two numbers of dice, consider the values as n-1 until n=7, and the reverse of those values until n=12. This logic will always remain the same and can be easily visualized.

Sum of two dice = 1 2 3 4 5 6 7 8 9 10 11 12
-------------------------------------------------------------------------------------
Favourable Outcomes= 0 1 2 3 4 5 6 5 4 3 2 1

Favourable Outcomes/Total events
Now, for this question P(4 or 6)= (3+5)/36= 2/9.
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