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Many thanks for your rapid response. I understand your steps beside the last one:

"If the number of women has to be between 13 and 20, 18 is the only option. So you multiply the combined ratio with 3 and get 60 men as your answer."

Could you please explain to me why is has to be 18?

Thanks!
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NYC5648
Many thanks for your rapid response. I understand your steps beside the last one:

"If the number of women has to be between 13 and 20, 18 is the only option. So you multiply the combined ratio with 3 and get 60 men as your answer."

Could you please explain to me why is has to be 18?

Thanks!
As Bunuel wrote, it has to be a multiple of 6. For example if we would take 15 women(2.5 times as many as 6), the initial ratio would not provide integer values, because then we'd have a ratio of women to childrean of 5:12.5( initial ratio of 2:5 times 2.5) for example.
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Buneul,

if you may think this a shorter approach..


W:C = 2:5
C:M =3:4

When we combine ratios we get 6x:15x:20x

x has to be 3 for 6x >13 and <18
hence 20x=60
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Buneul,

if you may think this a shorter approach..


W:C = 2:5
C:M =3:4

When we combine ratios we get 6x:15x:20x

x has to be 3 for 6x >13 and <18
hence 20x=60

Yes, you can do this way too. Though it's basically the same.
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Thank you to both of you!!!!
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Woman : Children ................ Children : Men

2 ................ 5...............|| ....... 3 ............ 4

LCM of 3 & 5 = 15; Making it common

Woman : Children : Men

6 ............... 15 ....... 20

Woman are between 13 & 20

Only factor of 6 between 13 & 20 is 3; Multiplying by 3

Men = 20 * 3 = 60
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Bunuel

I have a doubt. Please help me.

I did the problem like this:

w/c =2/5 c/m=3/5 therefore w:m=6:20

I further simplified the ratio of w:m as 3:10

now since the number of women is between 13 and 20.

Both 5 (5*3=15) and 6 (6*3=18) fit. Is it wrong to simplify the ratio like this?

thanks
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Bunuel

I have a doubt. Please help me.

I did the problem like this:

w/c =2/5 c/m=3/5 therefore w:m=6:20

I further simplified the ratio of w:m as 3:10

now since the number of women is between 13 and 20.

Both 5 (5*3=15) and 6 (6*3=18) fit. Is it wrong to simplify the ratio like this?

thanks

The number of women cannot be 15 because from W:C = 2:5 it follows that the number of women is a multiple of 2 (even).
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