What is the value of n if the sum of the consecutive odd

Question

What is the value of n if the sum of the consecutive odd intergers from 1 to n equals 169?

A) 47 
B) 25 
C) 37 
D) 33 
E) 29

EMPOWERgmatRichC · Accepted Answer

Hi All,

The GMAT is based heavily on patterns; your ability to recognize (or discover) patterns will help you to speed up and score at a higher level on Test Day. In "sequence" questions, at least one pattern will exist (the sequence has to based on a pattern; it's called a "sequence" because there's some "rule" that governs the sequence). In a prompt such as this, if you don't immediately see the pattern, then you can figure it out with a bit of experimentation.

Here, we're told to take the SUM of the positive ODD integers from 1 to N..... There's a pattern to this sequence; let's figure out what it is....

If N = 3
2 terms
1 + 3 = 4

If N = 5
3 terms
1 + 3 + 5 = 9

If N = 7
4 terms
1 + 3 + 5 + 7 = 16

Look at the sums. Do you recognize a pattern?
4....9......16......they're all PERFECT SQUARES!!!!

The next part of the question tells us the SUM of the terms in this sequence = 169 which is ALSO a perfect square (it's 13^2), so we can use this deduction along with the existing pattern we discovered to figure out the answer to the question.

169 = 13^2 = 13 terms

So we need the first 13 positive ODD integers starting with 1. We can physically list them out, if necessary...
1 3 5 7 9
11 13 15 17 19
21 23 25

Final Answer:  B: 25

GMAT assassins aren't born, they're made,
Rich

mau5 · Answer

Sum of the odd consecutive integers from 1 to n, where the # of terms is N :  N^2 .

Thus,  N^2 = 169 : N=13.

Thus, there are 13 terms in the series, and 13th term :First term+(# of terms-1)*Common difference : 1+(13-1)*2 = 25

B.

seabhi · Answer

Ans: 25

# of terms = (n-1/2)+1 {(last term - first term)/2+1|
Sum = (1+n)/2 * # of terms
= (n+1)^2/4= 169
n+1 = 13*2
n+1 = 26
n=25.

iNumbv · Answer

Before you tackle this question you must first understand that the question is comprised of two key parts, 1st is finding out how many  terms  is in that sequence and 2nd what  actual number value  that term is. In an arithmetic progression, in this case consecutive odd integers 1, 3, 5, ...., there are two set of rules.

Rule #1 (Arithmetic Sequence): xn = a + d(n-1) Identifies what the actual # in the sequence would be. Each number in the sequence has a term such as 1(is the first term), 3(is the second term) and so on. So if I were to ask you to find out what the 10th term is of that sequence you would use that formula to find that value. 
a=1 (first term)
d=2 (the common difference) remember in the sequence 1, 3, 5, 7 the common difference is always 2

*On a side note we use n-1 because we don't have d in the first term, therefore if we were solving for the first term we would get 0 as n-1 and 0 times d would give us 0, leaving only the first term. This works regardless what your first term is in any sequence.

But remember the question asks " What is the  value  of n if the sum of the consecutive odd integers from 1 to n equals 169?" which means we first need a consecutive sequence that sums up to 169 and than find what the value of the n is, in this case it would be the last number in that sequence. In order to find that we first need to know  how many terms  (how many of the n there is) in order to be able to plug n in this formula given we know what the sum is. For that to happen we need to use Rule #2.

Rule #2 (Summing an arithmetic series): 169 = n/2(2a+(n-1)d). Given the question gives us what the sum is (169 in this case) we would simply use this formula to solve for n. Once we solve for n (13 in this case) we can simply plug n into the first formula (rule 1) and find the value.

It feels very confusing and difficult at first, but once you identify the steps all you need to do is plug and play. We have the sum (169) of a sequence, the number of terms in that sequence is (unknown). Rule #2 tells us how many numbers there are in that sequence and Rule #1 gives us what that last term is.

PareshGmat · Answer

Answer = B = 25

Addition of consecutive odd integers is a perfect square, it means  \sqrt{169} = 13  consecutive odd numbers are added.

13 = \frac{n-1}{2} + 1

n = 25

ScottTargetTestPrep · Answer

Since sum = average x quantity:

169 = (n + 1)/2 x

169 = (n^2 - 1)/4 + (n + 1)/2

Multiplying the equation by 4, we have:

676 = n^2 - 1 + 2(n + 1)

676 = n^2 - 1 + 2n + 2

n^2 + 2n - 675 = 0

(n - 25)(n + 27) = 0

n = 25 or n = -27

Since n can’t be negative, n = 25.

Answer: B

Abhishek009 · Answer

n^2 = 169

Or,  n = 13

Now, sum of 13 consecutive odd integers from 1 is  169 ...

So, the 13 the no is  13*2 - 1 = 25 , Answer must be (B)

Samriddhi0603 · Answer

anyone who has similar questions

Bunuel · Answer

Check below: https://gmatclub.com/forum/what-is-the- ... 44620.html https://gmatclub.com/forum/what-is-the- ... 36544.html https://gmatclub.com/forum/the-sum-of-t ... 32773.html https://gmatclub.com/forum/the-sum-of-t ... 09368.html https://gmatclub.com/forum/if-the-sum-o ... 06063.html Hope it helps.

What is the value of n if the sum of the consecutive odd

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What is the value of n if the sum of the consecutive odd

Prep Toolkit

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My Rewards