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Bunuel
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Since first equation has equal roots, Let us call it "a",
Since first equation and second equation has one root in common, lets call the roots of second equation as "a" (common) and "b"
Product of roots of a quadratic equation in the forms ax^2+bx+c is (c/a)
Sum of roots of a quadratic equation in the forms ax^2+bx+c is (-b/a)

Thus a^2=(-n) from the first equation
ab=-15

a+a=-m
a+b=-m

2a=a+b
a=b

Substituting in ab=-15, a^2=-15

Since a^2=(-n)-----> n=15

Where did I go wrong?
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findingmyself
Since first equation has equal roots, Let us call it "a",
Since first equation and second equation has one root in common, lets call the roots of second equation as "a" (common) and "b"
Product of roots of a quadratic equation in the forms ax^2+bx+c is (c/a)
Sum of roots of a quadratic equation in the forms ax^2+bx+c is (-b/a)

Thus a^2=(-n) from the first equation
ab=-15

a+a=-m
a+b=-m

2a=a+b
a=b

Substituting in ab=-15, a^2=-15

Since a^2=(-n)-----> n=15

Where did I go wrong?

Your mistake is assuming the two equations share a common root. The question never says that.
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I like the solution - it’s helpful.
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I like the solution - it’s helpful.
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I did not quite understand the solution. where does k squared come from?
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Mahi_M
I did not quite understand the solution. where does k squared come from?

Could you please tell me where do you see k^2 in the solution? There are two different solutions given here. Which one are you referring to? Also, have you had a chance to review other solutions given in the thread?
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I did not quite understand the question and I like the solution - it’s helpful. I feel that the question is phrased in a wrong manner. Especially the part where it says y is a varibale, and m is a constant, is 3.
This sentence shows me, that 3=m and not y(as it should be)
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ArinK2101
I did not quite understand the question and I like the solution - it’s helpful. I feel that the question is phrased in a wrong manner. Especially the part where it says y is a varibale, and m is a constant, is 3.
This sentence shows me, that 3=m and not y(as it should be)
The phrasing is standard and not incorrect. The clause “one of the roots ... is 3” grammatically and mathematically refers to the variable y, not to the constant m. The sentence “where y is a variable and m is a constant” is simply defining symbols before stating a property of the roots. There is no valid reading in which 3 could be interpreted as m.
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