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Bunuel niks18 chetan2u KarishmaB GMATPrepNow pushpitkc generis

Quote:
If \(@x\) is the number of distinct positive divisors of \(x\), what is the value of \(@(@90)\)?

Quote:
Finding the Number of Factors of an Integer

First make prime factorization of an integer \(n=a^p*b^q*c^r\), where \(a\), \(b\), and \(c\) are prime factors of \(n\) and \(p\), \(q\), and \(r\) are their powers.

The number of factors of \(n\) will be expressed by the formula \((p+1)(q+1)(r+1)\). NOTE: this will include 1 and \(n\) itself.

Correct, but is not question asking us the distinct number of factors and not a TOTAL number of factors?

90 can be factorized in terms of primes as \(3^2\) , 2 and 5
UNIQUE Factors will be only 2,3 and 5. Am I correct?
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adkikani
Bunuel niks18 chetan2u KarishmaB GMATPrepNow pushpitkc generis

Quote:
If \(@x\) is the number of distinct positive divisors of \(x\), what is the value of \(@(@90)\)?

Quote:
Finding the Number of Factors of an Integer

First make prime factorization of an integer \(n=a^p*b^q*c^r\), where \(a\), \(b\), and \(c\) are prime factors of \(n\) and \(p\), \(q\), and \(r\) are their powers.

The number of factors of \(n\) will be expressed by the formula \((p+1)(q+1)(r+1)\). NOTE: this will include 1 and \(n\) itself.

Correct, but is not question asking us the distinct number of factors and not a TOTAL number of factors?

90 can be factorized in terms of primes as \(3^2\) , 2 and 5
UNIQUE Factors will be only 2,3 and 5. Am I correct?

Those are prime factors.

Distinct number of factors is the same as the total number of factors.
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adkikani
Bunuel niks18 chetan2u KarishmaB GMATPrepNow pushpitkc generis

Quote:
If \(@x\) is the number of distinct positive divisors of \(x\), what is the value of \(@(@90)\)?

Quote:
Finding the Number of Factors of an Integer

First make prime factorization of an integer \(n=a^p*b^q*c^r\), where \(a\), \(b\), and \(c\) are prime factors of \(n\) and \(p\), \(q\), and \(r\) are their powers.

The number of factors of \(n\) will be expressed by the formula \((p+1)(q+1)(r+1)\). NOTE: this will include 1 and \(n\) itself.

Correct, but is not question asking us the distinct number of factors and not a TOTAL number of factors?

90 can be factorized in terms of primes as \(3^2\) , 2 and 5
UNIQUE Factors will be only 2,3 and 5. Am I correct?

How about 6? Isn't that a unique factor too? What about 15? etc
As Bunuel said, no of factors is the same as unique factors. Note that we do not count 3 twice

\(90 = 2*3^2 * 5\)

Distinct Prime factors are 2, 3 and 5.

All unique factors are
1, 2, 3, 5, 6, 9, 10, 15, 18, 30, 45, 90
Total 12 factors
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Hey can please someone explain me why we are considering here the total number of factors and not distinct in sense of that 2,3, 5 are just three different factors ?
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JohannesR1996
Hey can please someone explain me why we are considering here the total number of factors and not distinct in sense of that 2,3, 5 are just three different factors ?

2, 3, and 5 are prime factors of 450. While 1 | 2 | 3 | 5 | 6 | 9 | 10 | 15 | 18 | 25 | 30 | 45 | 50 | 75 | 90 | 150 | 225 | and 450 are positive factors of 450.
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I think this is a high-quality question. Great question, even better soln
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I have edited the question and the solution by adding more details to enhance its clarity. I hope it is now easier to understand.
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I like the solution - it’s helpful.
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I like the solution - it’s helpful.
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Since, For function #, #x represents the number of distinct positive divisors of the positive integer which means we need to calculate the total number of factors.

#120 = 2 * 3^2 * 5
So total factors are (1+1)*(2+1)*(1+1) = 12

#(#120) = #12

#12 = 2^2 *3

So total no.of factors = 3*2 = 6

So #(#120) = 6

Option D is correct
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