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Bunuel
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Answer choice E. I was not sure how to attack this one and am sure there is a much easier way. If your long division skills are up to par, then it shouldn't take more than 2 minutes to answer. Each answer choice offers only a couple of possibilities for x so I just divided 899 by each possibility until one of them worked.

A. can be eliminated because 899 is not divisible by 2, 3, or 5
B. can be eliminated because 899 is not divisible by 11 or 13
C. can be eliminated because 899 is not divisible by 17 or 19
D. can be eliminated because 899 is not divisible by 23
E. this tells us x is either 29 or 31 and 899 is divisible by both (29x31=899)

Answer choice E!
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Bunuel

Tough and Tricky questions: Number Properties.



The smallest prime factor of 899 is \(x\). Which of the following is true of \(x\)?

A. \(1 \lt x \le 7\)
B. \(7 \lt x \le 14\)
C. \(14 \lt x \le 21\)
D. \(21 \lt x \le 28\)
E. \(28 \lt x \le 35\)

Kudos for a correct solution.

Note that 899 <900 and \(\sqrt{900}\)=30...so prime factor is below 30...

Note that it is always better to start with C option as we can easily rule 2,3,5 and 7...

In Option D between 21 and 28 there is only 1 prime and we can find whether 23 is that factor or not quickly...It is not because \(899/23\neq {Integer}\)

In option E we have 29,31, as prime but 31 is ruled out...and 899/29=Integer so ans is E..
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Answer = E

899 = 900 - 1

\(= 30^2 - 1^2\)

= (30+1)(30-1)

= 31 * 29

29 is the smallest factor

One more approach

899 = 1000 - 100 - 1

\(= 10^3 - 10^2 - 1\)

\(= 10^2(10-1) - 1\)

\(= 10^2 * 3^2 - 1\)

\(= (10*3)^2 - 1^2\)

= (30+1)(30-1)

= 31 * 29
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I've noticed that for many "medium" and "hard" level questions, there are tricks and ways to look at it that simplify the answer. If 899 is really close to 900, there's probably a reason for it and 900 can be used in some way or another, as the GMAT won't ask you a question that can't be done within a reasonable amount of time (e.g. a question won't require a math genius to do a problem by purely chugging through it in 10 minutes - no Good Will Hunting-hard questions here). It's daunting to look at, at first, but it's simpler if you keep that in mind - it's a common theme on GMAT questions and a good strategy to utilize. Of course, this sort of question is much easier if you already know how to approach this kind of question.
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I solved it by two methods
First method => Brute Force
Here we have to check everything and would take about 3 minutes (maybe 4 for someone like me)
Best way is to look for a technique so that we can prime factorize
Here 899 = 900-1=> 30^2-1^2=> 31*29 => BOOM ...!!!! 29 is the smallest prime factor
SMASH that E

First 26 primes =>
2
3
5
7
11
13
17
19
23
29
31
37
41
43
47
53
59
61
67
71
73
79
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899 = 900-1 (fancy little way to utilize what we know about (x2-1))
......= (30+1)(30-1) = (31)(29) --> BOTH PRIMES

Thus E is the correct answer.
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900 which is 1 more than 899 has a factor of 30. So,

=> 899 = 900 - 1

=> \(899 = 30^2 - 1^2 = (30 - 1) (30 + 1) = 29 * 31\)

So, 'x' : 28 < x < 35.

Answer E
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