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Bunuel
In a certain game, each player scores either 2 points or 5 points. If n players score 2 points and m players score 5 points, and the total number of points scored is 50, what is the least possible positive difference between n and m?

A. 1
B. 3
C. 5
D. 7
E. 9

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(5+2)*7=49
If m = 8; n=5;n-m=3
If m=6;n=10; n-m=4

IMO B

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Bunuel
In a certain game, each player scores either 2 points or 5 points. If n players score 2 points and m players score 5 points, and the total number of points scored is 50, what is the least possible positive difference between n and m?

A. 1
B. 3
C. 5
D. 7
E. 9

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With "x" is the difference between n and m, we have:
2n+5m=50 <-> 2n+5(n+x)=50 <-> 7n+5x=50 <-> n=(50-5x)/7
Now the task becomes: what is x to make n an integer (because n is the number of players who score 2 points, n must be an integer)
if x=1: n= 45/7 --> out
if x=3: n= (50-15)/7 = 5 (integer) --> correct!

Hope this helps :)
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I did it a bit differently:

2n + 5m = 50
=> 2n = 50 - 5m
=> 2n = 5 (10-m).

Now... m MUST be positive, so really the largest m can be is 9 but then the equation is not possible.
So we go to the next number, 8, and then n = 5.
Then we go to 7; the equation is not possible..
Then we go to 6; n = 10 ...
You can technically STOP here because the difference between 8 and 5 (3) is smaller than the difference between 10 and 6 (4).
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