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Mesto
The ratio of the present ages of a man and his wife is 5 : 4. Which of the following can't be a possible ratio of their ages 20 years ago?

A) 7: 5
B) 3: 2
C) 13:10
D) 6: 5
E) 6: 4

Not sure on this method

5x-20/4x-20 = 6/5
Therefore x=-20
Age cannot be negative.
So D
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also used fraction properties

5/4 initial should lead to increase the fraction after minusing 20 in num. an denom. All we should do is compare 5/4 with answer options

A. 7/5>5/4-possible
B. 3/2>5/4-possible
C. 13/10>5/4-possible
D. 6/5<5/4- not possible
E. 6/4>5/4-possible

it is D
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Mesto
The ratio of the present ages of a man and his wife is 5 : 4. Which of the following can't be a possible ratio of their ages 20 years ago?

A) 7: 5
B) 3: 2
C) 13:10
D) 6: 5
E) 6: 4

Hello Experts,

Any thoughts on the above question?
Thanks.
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Mesto
The ratio of the present ages of a man and his wife is 5 : 4. Which of the following can't be a possible ratio of their ages 20 years ago?

A) 7: 5
B) 3: 2
C) 13:10
D) 6: 5
E) 6: 4


The question is based on the concept:

When we add the same positive integer to the numerator and the denominator of a positive fraction, the fraction increases if it is less than 1 (but remains less than 1) and decreases if it is more than 1 (but remains more than 1). That is, we can say, that the fraction is pulled toward 1 in both the cases.

When we subtract the same positive integer from the numerator and the denominator of a positive fraction, the fraction decreases further if it is less than 1 and increases further if it is more than 1. That is, we can say, that the fraction is pushed further away from 1 in both the cases. An assumption here is that the positive number subtracted is less than both the numerator and the denominator.

This is explained in detail here: https://www.gmatclub.com/forum/veritas-prep-resource-links-no-longer-available-399979.html#/2011/0 ... round-one/

The given ratio is 5/4 which is the same as 25/20 or 50/40 etc.

When we subtract 20 from each of the numerator and the denominator of this fraction, it will be pushed away from 1 i.e. will become greater than 5/4. All the given options are greater than 5/4 except 6/5.
Hence answer will be (D).

Hello Karishma,

I read the article on your blog and now I understand the concept.
Many thanks!
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This is a problem that can be solved in about 30 seconds.

Refer to the video done by GMATPrepNow in the answer to the below problem.

The direction of increase and decrease is what you need to focus on in this problem.

Only D is the answer that correctly applies the properties of fractions as you increase the N and D by the same amount the closer to 1 the fraction becomes.

This is true for both fractions that are greater than 1 and fractions, in this case, and fractions that are less than 1.


https://gmatclub.com/forum/if-the-ratio ... l#p2461276


You should think back to your days in Calculus class when you discuss asymptotes. As the denominator gets infinitely large it approaches 0. As both denominator and numerator get infinitely large the fraction approaches 1.

Add 100 to each interval:

4/5 => 4 + 100 / 5 + 100 = 104 / 105 ~ this is very close to 1

Now add 1,000,000 to the D and N:

4 +1,000,000 / 5 + 1,000,000 . = 1,000,004 / 1,000,005 ~ this is essentially 1


The same phenomenon happens to fractions that are greater than 1. The only difference is the fraction approaches 1 from a number greater than 1 as is happening in this problem.


The answers are given to you with numerators that are very easily convert into fractions of 100 or actual decimals.


A 7/5 => 1.4
B 3/2 => 1.5
C 13/10 => 1.3
D 6/5 => 1.2
E 6/4 => 1.5


Only one of these is a decrease from 1.25 which means only one is decreasing to approach 1.


A 7/5 => 1.4 > 1.5
B 3/2 => 1.5 > 1.5
C 13/10 => 1.3 > 1.5
D 6/5 => 1.2 < 1.5
E 6/4 => 1.5 > 1.5
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Mesto
The ratio of the present ages of a man and his wife is 5 : 4. Which of the following can't be a possible ratio of their ages 20 years ago?

A) 7: 5
B) 3: 2
C) 13:10
D) 6: 5
E) 6: 4

Let the age of man be 5x and age of his wife be 4x

20 years ago
Ratio of their ages = (5x-20)/(4x-20)
1 + x/(4x-20)

1. 7/5
x/(4x-20) = 2/5
5x = 8x - 40
x = 40/3

2. 3/2
x/(4x-20) = 1/2
2x = 4x-20
x = 10

3. 13/10
x/(4x-20) = 3/10
10x = 12x - 60
x = 30

4. 6/5
x/(4x-20) = 1/5
5x = 4x-20
x= -20
Not possible since ages are positive

5. 6/4 = 3/2
Discussed above in 2.

IMO D

Posted from my mobile device
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I couldn't think of a way to solve it so this is how I reached to the correct answer choice.

The question says all are correct ratios except for one. Now if you look at answer choice D and E they are 6:5 and 6:4. If one part of the new ratio is 6 then it will have only one other unique part which means in a ratio with one part as 6k the other will either be 5k or 4k. Which means definitely one of these is wrong. There is a 3:2 in the answer choices which means that 6:4 is definitely correct (Can't have two correct answers). So it has to be 6:5 which is incorrect.
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