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Updated on: 14 May 2024, 12:36
Originally posted by BrentGMATPrepNow on 24 Oct 2016, 09:39.
Last edited by Bunuel on 14 May 2024, 12:36, edited 2 times in total.
Last edited by Bunuel on 14 May 2024, 12:36, edited 2 times in total.
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
45%
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Question Stats:
68% (01:47) correct
32%
(02:14)
wrong
based on 368
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How many positive, 3-digit integers contain at least one 7?
A) 171
B) 200
C) 243
D) 252
E) 271
A) 171
B) 200
C) 243
D) 252
E) 271
Here's our video solution: https://www.gmatprepnow.com/module/gmat ... /video/784
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16 Aug 2019, 06:40
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GMATPrepNow
finding those with at least a 7 (XX7,X77,777) is the same as finding those without a 7 and subtracting it from the total
num of digits: 0 to 9 = 10
3-digit positive numbers: 999-100+1=900
first digit ≠ 0 or 7: 8 options
second digit ≠ 7: 9 options
third digit ≠ 7: 9 options
total 3-digit num ≠ 7: 8*9*9=648
total 3-digit with at least a 7: total - no 7 = 900 - 648 = 252
Answer (D).
General Discussion
Updated on: 24 Oct 2016, 10:51
Originally posted by acegmat123 on 24 Oct 2016, 10:13.
Last edited by acegmat123 on 24 Oct 2016, 10:51, edited 1 time in total.
Last edited by acegmat123 on 24 Oct 2016, 10:51, edited 1 time in total.
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Contains only one 7:
7XX: 1*9*9 = 81
X7X: 8*1*9 = 72
XX7: 8*9*1 = 72
Contains two 7s:
77X: 1*1*9=9
X77: 8*1*1 = 8
Contains three 7s:
777: 1
Total 243
C
Edited: Editing as per GMATPrep's comments
Sent from my iPhone using GMAT Club Forum mobile app
7XX: 1*9*9 = 81
X7X: 8*1*9 = 72
XX7: 8*9*1 = 72
Contains two 7s:
77X: 1*1*9=9
X77: 8*1*1 = 8
Contains three 7s:
777: 1
Total 243
C
Edited: Editing as per GMATPrep's comments
Sent from my iPhone using GMAT Club Forum mobile app
