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13 Feb 2017, 03:35
Kudos
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B
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Difficulty:
55%
(hard)
Question Stats:
58% (01:43) correct
42%
(01:46)
wrong
based on 185
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A regular icosahedron is a three-dimensional solid composed of twenty equilateral triangular faces, with five faces meeting at each vertex. How many vertices does a regular icosahedron have?
A. 5
B. 12
C. 20
D. 33
E. 60
A. 5
B. 12
C. 20
D. 33
E. 60
13 Feb 2017, 12:38
Kudos
Bookmarks
#of triangular vertices is 20*3=60
5 vertices/per icosahedron so 60/5=12.
B.
Not really sure though..
5 vertices/per icosahedron so 60/5=12.
B.
Not really sure though..
13 Feb 2017, 18:07
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Bunuel
Each triangle has 3 vertices, and there are 20 triangles in total.
So, the total number of triangle vertices = 3 x 20 = 60
Each vertex in the icosahedron is comprised of five triangle faces meeting at a point.
In other words, it takes 5 triangle vertices to make 1 icosahedron vertex .
We have 60 triangle vertices, so the TOTAL number of icosahedron vertices = 60/5 = 12
Answer: B
Cheers,
Brent
