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Henni
What is the probability that the sum of two dice will yield a 10 or lower?

A. 34/36
B. 33/36
C. 32/36
D. 31/36
E. 30/36

Its the question from Manhattan GMAT Number Proporties page 65.

Im not able to to understand ehy there are just three combination (5+6,6+5,6+6) and not 4 with the 6+6 again??

I´m such an idiot :)

There are 3 possible combination for to get higher than 10 from two dices:

D1 - 6 + D2- 6 = 12
D1 - 6 + D2- 5 = 11
D1 - 5 + D2- 6 = 11

Now total combinations = 6*6 = 36
Remaining combinations = 36 - 3 = 33

Hence, probability to get 10 or lower = 33/36.
Answer B.
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Hi All,

With this prompt, you might find it beneficial to 'write everything out' - while it would take a little bit of work, you would be able to physically see all of the possibilities, which would make dealing with the concept easier.

Since we are rolling two 6-sided dice, there are (6)(6) = 36 possible outcomes. Those outcomes are....

11,12,13,14,15,16
21,22,23,24,25,26
31,32,33,34,35,36
41,42,43,44,45,46
51,52,53,54,55,56
61,62,63,64,65,66

Of these 36 outcomes you can either calculate what you WANT or what you DON'T WANT (and subtract that from the number 1). The second method is easier here...

There are 3 options that DO NOT fit what you're looking for.... 3/36 = 1/12

1 - 1/12 = = 11/12 = the options that you ARE looking for.

Final Answer:
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Try to first figure out is calculating the favorable probability easy or calculating the non-favorable probability is easy.Here calculating the non favorable probability would be easy.So non favorable event would be getting a 11 or 12.

Probability of getting a 11 is Favorable outcomes/Total Outcomes=2/36.
Probability of getting a 12 is 1/36
So required probability=1-(1/36+2/36)
=1-3/36=33/36
So answer is B
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Henni
What is the probability that the sum of two dice will yield a 10 or lower?

A. 34/36
B. 33/36
C. 32/36
D. 31/36
E. 30/36

Its the question from Manhattan GMAT Number Proporties page 65.

Im not able to to understand ehy there are just three combination (5+6,6+5,6+6) and not 4 with the 6+6 again??

I´m such an idiot :)

sum 10 ; 5,6; 6,5 & 6,6
so P ; 3/36
and P <=10 ; 1-3/36 ; 33/36
IMO B
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P(<=10) = 1 - P (>10)

= 1 - P ( 11 or 12)

=1 - 3/36

=33/36
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We need to find What is the probability that the sum of two dice will yield a 10 or lower?

As we are rolling two dice => Number of cases = \(6^2\) = 36

Now the sum of the two rolls will be between 1+1=2 (when we get 1 on both the dice) and 6+6 = 12 (when we get 6 on both the dice)

So, out of the 36 cases only three cases are there where the sum will be higher than 10. These cases are (5,6), (6,5) and (6,6)
=> Cases with sum as 10 or lower = 36 - 3 = 33

=> Probability that Sum of two dice will yield 10 or lower = \(\frac{33}{36}\)

So, Answer will be B
Hope it helps!

Watch the following video to learn How to Solve Dice Rolling Probability Problems

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