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Bunuel
If 0 < x ≤ 100, what is the probability that x(x + 1) is a multiple of 4?

A. 1/8
B. 1/4
C. 33/100
D. 1/2
E. 29/50

From 1 to 100 there are: \(Number.Terms=Last.term-First.term+1=100-1+1=100\) total outcomes.

If x is a multiple of 4 then x(x+1) = multiple of 4.
If x+1 is a multiple of 4 then x(x+1) = multiple of 4.

From 1 to 100 there are: \(Number.Multiples=\frac{Largest.multiple-Smallest.multiple}{Multiple}+1=\frac{100-4}{4}+1=25\) multiples of 4 that fit \(x\), and \(25\) multiples of 4 that fit \(x-1\).

Probability is: \(\frac{Favorable.Outcomes}{Total.Outcomes}=\frac{(25+25)}{100}=1/2\).

(D) is the answer.
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Bunuel
If 0 < x ≤ 100, what is the probability that x(x + 1) is a multiple of 4?

A. 1/8
B. 1/4
C. 33/100
D. 1/2
E. 29/50

Hi EgmatQuantExpert, niks18, chetan2u,

Can you please help me to clarify my doubt.

The question states that \(0 < x ≤ 100\), so for all the Integers value of \(x\) the answer will be \(\frac{50}{100}\). However, here x can be decimals also for ex - \(x\)= \((\sqrt{17}-1)/2\), x = \((\sqrt{65}-1)/2\).

Can you please let me know if I am missing anything here.
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rahul16singh28
Bunuel
If 0 < x ≤ 100, what is the probability that x(x + 1) is a multiple of 4?

A. 1/8
B. 1/4
C. 33/100
D. 1/2
E. 29/50

Hi EgmatQuantExpert, niks18, chetan2u,

Can you please help me to clarify my doubt.

The question states that \(0 < x ≤ 100\), so for all the Integers value of \(x\) the answer will be \(\frac{50}{100}\). However, here x can be decimals also for ex - \(x\)= \(\frac{\sqrt{17}-1}{2}\), x = \(\sqrt{65}-1/2\).

Can you please let me know if I am missing anything here.

Hi rahul16singh28

Here x is a multiple of 4. Multiples of 4 cannot be decimals (0.4=2/5 is not a multiple of 4), they will have to be an integer. so probability has to be between favorable integer values which are (25+25) and total integers possible which is 100
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X = 4,8,....100 - 25 count
X+1 = 4,8,.....100- 25 count

Total = 25 + 25 = 50

Answer : 50/100 = 1/2
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Bunuel
If 0 < x ≤ 100, what is the probability that x(x + 1) is a multiple of 4?

A. 1/8
B. 1/4
C. 33/100
D. 1/2
E. 29/50

Hi EgmatQuantExpert, niks18, chetan2u,

Can you please help me to clarify my doubt.

The question states that \(0 < x ≤ 100\), so for all the Integers value of \(x\) the answer will be \(\frac{50}{100}\). However, here x can be decimals also for ex - \(x\)= \(\frac{\sqrt{17}-1}{2}\), x = \(\sqrt{65}-1/2\).

Can you please let me know if I am missing anything here.

Hi rahul16singh28

Here x is a multiple of 4. Multiples of 4 cannot be decimals (0.4=2/5 is not a multiple of 4), they will have to be an integer. so probability has to be between favorable integer values which are (25+25) and total integers possible which is 100

Hi niks18,

I think here we have to find out if x(x+1) is a multiple of 4. If we take \(x\)= \(\sqrt{17}-1/2\), then x(x+1) is a multiple of 4.
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Quote:
Hi niks18,

I think here we have to find out if x(x+1) is a multiple of 4. If we take \(x\)= \(\sqrt{17}-1/2\), then x(x+1) is a multiple of 4.

Hi rahul16singh28

if \(x= \sqrt{17}-\frac{1}{2}\), then \(x+1=\sqrt{17}-\frac{1}{2}+1=\sqrt{17}+\frac{1}{2}\)

now \(x(x+1)=(\sqrt{17}-\frac{1}{2})(\sqrt{17}+\frac{1}{2})=17-\frac{1}{4}\) which is not a multiple of \(4\).

Point is non integers cannot be multiples of integers otherwise every non integer can be multiple of integer
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niks18
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Hi niks18,

I think here we have to find out if x(x+1) is a multiple of 4. If we take \(x\)= \(\sqrt{17}-1/2\), then x(x+1) is a multiple of 4.

Hi rahul16singh28

if \(x= \sqrt{17}-\frac{1}{2}\), then \(x+1=\sqrt{17}-\frac{1}{2}+1=\sqrt{17}+\frac{1}{2}\)

now \(x(x+1)=(\sqrt{17}-\frac{1}{2})(\sqrt{17}+\frac{1}{2})=17-\frac{1}{4}\) which is not a multiple of \(4\).

Point is non integers cannot be multiples of integers otherwise every non integer can be multiple of integer

Hi niks18,

May be I am missing something silly here but what I meant was if \(x\)= \((\sqrt{17} - 1)/2\). True that non-integers cannot be multiple of Integer but here we have a case where product of 2 non-integer (x & x+1) is a multiple of integer for \(x\)= \((\sqrt{17} - 1)/2\) and this is what exactly we need to find.
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Bunuel
If 0 < x ≤ 100, what is the probability that x(x + 1) is a multiple of 4?

A. 1/8
B. 1/4
C. 33/100
D. 1/2
E. 29/50

Hi EgmatQuantExpert, niks18, chetan2u,

Can you please help me to clarify my doubt.

The question states that \(0 < x ≤ 100\), so for all the Integers value of \(x\) the answer will be \(\frac{50}{100}\). However, here x can be decimals also for ex - \(x\)= \((\sqrt{17}-1)/2\), x = \((\sqrt{65}-1)/2\).

Can you please let me know if I am missing anything here.

It was missing in the question that x is an integer.
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Bunuel
If 0 < x ≤ 100, what is the probability that x(x + 1) is a multiple of 4?

A. 1/8
B. 1/4
C. 33/100
D. 1/2
E. 29/50

Hi EgmatQuantExpert, niks18, chetan2u,

Can you please help me to clarify my doubt.

The question states that \(0 < x ≤ 100\), so for all the Integers value of \(x\) the answer will be \(\frac{50}{100}\). However, here x can be decimals also for ex - \(x\)= \((\sqrt{17}-1)/2\), x = \((\sqrt{65}-1)/2\).

Can you please let me know if I am missing anything here.

It was missing in the question that x is an integer.
:lol: :lol: :lol:

rahul16singh28 our problem is solved :thumbup: :thumbup: :thumbup: :thumbup:
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rahul16singh28
Bunuel
If 0 < x ≤ 100, what is the probability that x(x + 1) is a multiple of 4?

A. 1/8
B. 1/4
C. 33/100
D. 1/2
E. 29/50

Hi EgmatQuantExpert, niks18, chetan2u,

Can you please help me to clarify my doubt.

The question states that \(0 < x ≤ 100\), so for all the Integers value of \(x\) the answer will be \(\frac{50}{100}\). However, here x can be decimals also for ex - \(x\)= \((\sqrt{17}-1)/2\), x = \((\sqrt{65}-1)/2\).

Can you please let me know if I am missing anything here.


I solved this question with the assumption that x is an integer. :)

You did the right thing by not assuming it in the starting and considering all the possible cases. But given that GMAT does not test us on such complex matters, I felt that assuming x is an integer makes sense and it might just be miss a while framing the question, which Bunuel did clarify. :)


Regards,
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