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08 Jan 2018, 23:53
Kudos
Bookmarks
C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
55%
(hard)
Question Stats:
70% (03:23) correct
30%
(03:39)
wrong
based on 83
sessions
History
Date
Time
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Not Attempted Yet
A store sells three types of calculators, model A, model B and model C. The selling price of model A is $66, which is 120 percent that of model B, while the selling price of B is p percent of that of C. If the manufacturer sells 2000 calculators, 1/4 of which are model B, and an equal number of A and C models and the total revenue from the sale of calculators is $242,000, what is the value of p?
A. 60
B. 35
C. 25
D. 20
E. 15
A. 60
B. 35
C. 25
D. 20
E. 15
09 Jan 2018, 00:40
Kudos
Bookmarks
Hi everyone,
Prices:
A - 66$
B - 66*5/=55$
C - 55*100/p$
Quantity:
A - 2000*1/4=500
B - (2000-500)/2=750
C - 750
Equation:
500*55+750*66+750*55*100/p=242000 | divide both sides by 250
110+198+165*100/p=968
100/p=4
p=25
ANS: C
Please, Kudos
Prices:
A - 66$
B - 66*5/=55$
C - 55*100/p$
Quantity:
A - 2000*1/4=500
B - (2000-500)/2=750
C - 750
Equation:
500*55+750*66+750*55*100/p=242000 | divide both sides by 250
110+198+165*100/p=968
100/p=4
p=25
ANS: C
Please, Kudos
09 Jan 2018, 03:42
Kudos
Bookmarks
Bunuel
An easier calculation than the above, using smaller numbers, involves a shortcut using the logic of averages.
This is a Logical approach.
Instead of calculating the total revenue, we'll calculate the average revenue.
As there are 2000 calculators, the average revenue per calculator 242,000/2,000 = $121.
Since 1.2B = 66 then B=55.
Additionally as 2000/4=500 of the calculators are model B then (2000-500)/2 = 750 are model A and C.
Then the ratio A:B:C is 750:500:750 = 3:2:3
So if we take 3 units of A, 2 of B and 3 of C their average is the average revenue per calculator - $121.
3*66 + 2*55 + 3C = 121*8
198 + 110 +3C = 968
3C = 660
C = 220
Therefore B/C = 55/220 = 1/4 = 25%.
(C) is our answer.
