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Bunuel
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Bunuel
There are 125 members in the winter sports club. Of those, 20 do not ski or snowboard. If 1/3 of the people who ski also snowboard, and if the number of people who only snowboard is equal to 1/2 of the number of people who ski and snowboard, how many people only snowboard?

A. 15
B. 20
C. 30
D. 45
E. 60

Using Venn diagram
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Bunuel
There are 125 members in the winter sports club. Of those, 20 do not ski or snowboard. If 1/3 of the people who ski also snowboard, and if the number of people who only snowboard is equal to 1/2 of the number of people who ski and snowboard, how many people only snowboard?

A. 15
B. 20
C. 30
D. 45
E. 60

We can let k = the number of people who ski, n = the number of people who snowboard, and b = the number of people who do both. From the information given in the problem, we can create the equations:

k + n - b + 20 = 125,

(1/3)k = b,

and

n - b = (1/2)b

n - b = (1/2)(k/3k)

Simplifying the third equation, we have:

n - b = (1/6)k

Substituting ⅙k for n - b in the first equation, we have:

k + (1/6)k + 20 = 125

7/6 k = 105

k = 105 x 6/7

k = 90

Since the number of people who only snowboard is n - b, which is (1/6)k , the number of people who only snowboard is(1/6)(90) = 15.

Answer: A
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Bunuel
There are 125 members in the winter sports club. Of those, 20 do not ski or snowboard. If 1/3 of the people who ski also snowboard, and if the number of people who only snowboard is equal to 1/2 of the number of people who ski and snowboard, how many people only snowboard?

A. 15
B. 20
C. 30
D. 45
E. 60

Given:
1. There are 125 members in the winter sports club. Of those, 20 do not ski or snowboard.
2. 1/3 of the people who ski also snowboard,
3. the number of people who only snowboard is equal to 1/2 of the number of people who ski and snowboard

Asked: how many people only snowboard?

Total number of people to either ski or snowboard = 125-20=105

Let the number of people who ski be 3x
The number of people who only ski= 2x
The number of people who ski and snowboard = x
The number of people who only snowboard = x/2

Since 2x+x+x/2=105
x= 30

x/2 = 15
The number of people who only snowboard = 15

IMO A

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Bunuel
There are 125 members in the winter sports club. Of those, 20 do not ski or snowboard. If 1/3 of the people who ski also snowboard, and if the number of people who only snowboard is equal to 1/2 of the number of people who ski and snowboard, how many people only snowboard?

A. 15
B. 20
C. 30
D. 45
E. 60

solving it in 2x2 matrix

---ski----nski----total
sb--x/3---x/6----x/2
nsb--2x/3---20---2x/3+20
total--x-----125-x---125
solve for x
x/2+2x/3=105
x= 30
so only SB ; 30/2 ; 15
IMO A
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Bunuel
There are 125 members in the winter sports club. Of those, 20 do not ski or snowboard. If 1/3 of the people who ski also snowboard, and if the number of people who only snowboard is equal to 1/2 of the number of people who ski and snowboard, how many people only snowboard?

A. 15
B. 20
C. 30
D. 45
E. 60
Solution:

We can use the formula:

Total = Ski Only + Snowboard Only + Both + Neither

We can let the number of people who ski = x; therefore, x/3 = the number of people who do both and the number of people who snowboard only = x/6.

125 = (x - x/3) + x/6 + x/3 + 20

105 = 7x/6

630 = 7x

90 = x

Therefore, the number of people who only snowboard is Snowboard Only = x/6 = 15.

Answer: A
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There are 125 members in the winter sports club. Of those, 20 do not ski or snowboard. If 1/3 of the people who ski also snowboard, and if the number of people who only snowboard is equal to 1/2 of the number of people who ski and snowboard, how many people only snowboard?

Let the no. of members who ski = 6a,
According to the given scenario,
=> the no. of members who ski and snowboard = 2a
=> the no. of members who only snowboard = a

Now, Total members who ski or snowboard = no. of members who ski + no. of members who only snowboard
=> 125 - 20 = 6a + a
=> 105 = 7a
=> a = 15

Hence A
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Bunuel
There are 125 members in the winter sports club. Of those, 20 do not ski or snowboard. If 1/3 of the people who ski also snowboard, and if the number of people who only snowboard is equal to 1/2 of the number of people who ski and snowboard, how many people only snowboard?

A. 15
B. 20
C. 30
D. 45
E. 60
I think a table would give better visibility:
Let x be the number of people who ski (including both only ski and ski & snowboard):
SkiNo SkiTotal
Snowboardx*\(\frac{1}{3}\)x*\(\frac{1}{3}\)*\(\frac{1}{2}\)
No Snowboard20
Totalx125-x125

So we have an equation and solve for x:
x*\(\frac{1}{3}\)*\(\frac{1}{2}\) + 20 = 125-x
x=90

--> So number of people who only snowboard is 90*\(\frac{1}{3}\)*\(\frac{1}{2}\) =15
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