I think the answer is E since "Given a triangle ABC, the sum of the lengths of any two sides of the triangle is greater than the length of the third side". In this way, in statement (1), AB+BC=1+8=9=AC, thus such triangle does not exist. In this way, statement (1) is wrong as well.
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In △ABC, is any angle greater than 90°?
(1) AB = 2, BC = 8, AC = 9
(2) Sum of the greatest and the second greatest angle is 160°
If we have the lengths of sides of a triangle, then to determine whether the triangle is acute (all angles less than 90) or right angled (one angle = 90) or obtuse (one angle > 90); we should square all the three lengths of sides.
If square of longest side is smaller than the sum of squares of two smaller sides, its an acute angled triangle
If square of longest side is equal to the sum of squares of two smaller sides, its a right angled triangle
If square of longest side is greater than the sum of squares of two smaller sides, its an obtuse angled triangle
(1) As the lengths are given, we can square and determine the answer. Sufficient (Its obtuse by the way, so one angle will be > 90).
(2) If sum of two angles = 160, both could be less than 90 (80, 80) or one could be greater than 90 (100, 60). Not sufficient.
Hence
A answer