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Bunuel
6 ≤ |x| ≤ 8

1 ≤ |y| ≤2

3 ≤ |z| ≤ 4

If x, y, and z satisfy the inequalities shown, what is the least possible value of |x+y+z| ?

A. 0
B. 1
C. 2
D. 3
E. 4

Sir how to solve this question ?

least values for x can be 6 , y=1 and z 3 ,
Is there a (-) sign missing from the given expressions?

Dear Archit3110
Notice that possible values of x lies in: -8≤x≤-6 & 6≤x≤8. So we can conclude that -2≤y≤-1 & 1≤y≤2 and, -4≤z≤-3 & 3≤z≤4.
So, least possible value for |x+y+z| might be calculated as x=-6, y=2 & z=4, which equals 0.
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Use the answer choices to cheat. We see that there are no negative values so that makes our lives easier. Look to see whether 0 is obtainable given the ranges. It is.

x = -6
y = 2
z = 4

x + y + z = -6 + 2 + 4 = 0

A.
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From the answer choices we see the lowest possible is 0 which
So is |(-5)+2+3| = 0 also a right way to arrive?

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VeeB
From the answer choices we see the lowest possible is 0 which
So is |(-5)+2+3| = 0 also a right way to arrive?

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­No, because x can't = -5. Its absolute value must be between 6 and 8 inclusive, so if it's negative it must be between -8 and -6. 
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I am Still not Getting this Last part of Choosing Value of X Y & Z
RamSep
Archit3110
Bunuel
6 ≤ |x| ≤ 8

1 ≤ |y| ≤2

3 ≤ |z| ≤ 4

If x, y, and z satisfy the inequalities shown, what is the least possible value of |x+y+z| ?

A. 0
B. 1
C. 2
D. 3
E. 4

Sir how to solve this question ?

least values for x can be 6 , y=1 and z 3 ,
Is there a (-) sign missing from the given expressions?

Dear Archit3110
Notice that possible values of x lies in: -8≤x≤-6 & 6≤x≤8. So we can conclude that -2≤y≤-1 & 1≤y≤2 and, -4≤z≤-3 & 3≤z≤4.
So, least possible value for |x+y+z| might be calculated as x=-6, y=2 & z=4, which equals 0.
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I am Still not Getting this Last part of Choosing Value of X Y & Z
RamSep

Dear Archit3110
Notice that possible values of x lies in: -8≤x≤-6 & 6≤x≤8. So we can conclude that -2≤y≤-1 & 1≤y≤2 and, -4≤z≤-3 & 3≤z≤4.
So, least possible value for |x+y+z| might be calculated as x=-6, y=2 & z=4, which equals 0.
Think about it this way, we are asked to find least possible value of |x+y+z|, and when you glance the answer choices - you see the least value is 0, then go back to the question and see if you can get |x+y+z| = 0, if yes then that's the correct answer.
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