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Solution – Using Options



Given:
    • A boy purchased some chocolates from a shop for $120.
    • In the next shop he found that the price per piece of chocolate is $3 less than that charged at the previous shop.
    • Because of the lower price in the next shop, he figured out that he could have purchased 2 more chocolates in the next shop, compared to what he bought originally.

To find:
    • The number of chocolates he bought from the first shop

Approach and Working:
We know that 120/number of chocolates = price per chocolate

For the first shop,
    • 120/number of chocolates bought = price per chocolate
    • Therefore, number of chocolates bought must be a factor of 120 (at this point, we can discard option A and option C)

For the second shop,
    • 120/(number of chocolates bought + 2) = price per chocolate – 3
    • Therefore, (number of chocolates bought + 2) must also be a factor of 120 (at this point, we can discard option E)

At this point, we can check the remaining two options.
If number of chocolates bought = 8, then
    • Price per chocolate in the first shop = \(\frac{120}{8} = 15\)
    • Price per chocolate in the second shop = \(\frac{120}{(8 + 2)} = 12\)
    • And, 15 – 12 = 3, which satisfies our given condition.

Hence, the correct answer is option B.

Answer: B

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Solution – Using 1 Variable



Given:
    • A boy purchased some chocolates from a shop for $120.
    • In the next shop he found that the price per piece of chocolate is $3 less than that charged at the previous shop.
    • Because of the lower price in the next shop, he figured out that he could have purchased 2 more chocolates in the next shop, compared to what he bought originally.

To find:
    • The number of chocolates he bought from the first shop

Approach and Working:
Let us assume that the number of chocolates he bought from the first shop is n.
    • Price per chocolate in the first shop = \(\frac{120}{n}\)

Number of chocolates he could have bought from the second shop = n + 2
    • Price per chocolate in the second shop = \(\frac{120}{(n + 2)}\)

As per the given information,
    • \(\frac{120}{n} – \frac{120}{n+2} = 3\)
    Simplifying, we get n = 8

Hence, the correct answer is option B.

Answer: B

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Solution – Using 2 Variables



Given:
    • A boy purchased some chocolates from a shop for $120.
    • In the next shop he found that the price per piece of chocolate is $3 less than that charged at the previous shop.
    • Because of the lower price in the next shop, he figured out that he could have purchased 2 more chocolates in the next shop, compared to what he bought originally.

To find:
    • The number of chocolates he bought from the first shop

Approach and Working:
Let us assume that the number of chocolates he bought from the first shop is n, and the price of each chocolate in the first shop is p
    • Therefore, we can say n x p = 120 …… (1)

Number of chocolates he could have bought from the second shop = n + 2
And the price of each chocolate in the second shop = p – 3
    • Therefore, we can say that (n + 2) (p – 3) = 120 …… (2)

Solving the equations (1) and (2), we get n = 8 and p = 15

Hence, the correct answer is option B.

Answer: B

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