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Shobhit7
17 different combinations means: 5, 10, 15... up to 85.


Now, with 12 coins, we can create 85c as : 10c*5 + 5c*7

So, Total 10c coins: 5

Ans C

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Hi,

Can you please explain in detail how you solved this?
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chetan2u Bunuel VeritasKarishma Can you please explain this .What 17 different combinations infer here ?
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We can make 17(>12) different values. She must have atleast 1 5-cent coin; hence she can obtain all the multiples of 5 less than or equal to 5x+10y, where x is number of 5-cent coins and y is number of 10-cent coins.

\(x= \frac{120-17*5}{5}= 7\)

\(y=12-7=5\)


Bunuel
Claudia has 12 coins, each of which is a 5-cent coin or a 10-cent coin. There are exactly 17 different values that can be obtained as combinations of one or more of her coins. How many 10-cent coins does Claudia have?

(A) 3
(B) 4
(C) 5
(D) 6
(E) 7
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Hi nick1816, How do we get 120? What is that?
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She has 12 coins: some are 5 cents and some are 10 cents

Any particular combination of a 10 cent coin or a 5 cent coin will always give us a multiple of 5.

Because we are allowed to make every unique combination of coins that is possible, it should be the case that we can make every multiple of 5 within the following range ————->

From 1 coin of 5 cents


To choosing all 12 coins to get the maximum SUM

We are told there are 17 unique totals that can be made.


The first 17 multiples of 5 are from:

[5 through 85]


The correct amount of 5 cent coins and 10 cent coins should give us a MAX SUM Total of 85 cents when we Choose All 12 coins

every other multiple of 5 prior to 85 will be able to be made as a SUM through choosing some combination of 5 cent and 10 cent coins

Thus, we are looking for which combination of 12 coins will give us a MAX total of 85 cents when we choose all 12 of them and add them up?

(C) Ten cent coins = 5

Which means Five cent coins = 7

If we choose all 12 coins, the MAX SUM total will be:

(5 coins) (10 cents) + (7 coins) (5 cents) =

50 + 35 = 85 cents

This is the amount we would get on our 17th final unique combination when we choose all the coins. we can not create any higher SUM and we should be able to create every other Multiple of 5 prior to 85 by choosing some combination of Five Cent and Ten Cent coins.

This will result in 17 possible Unique Sums: 5, 10, 15......... all the way to MAX 85


Thus,

(C) 5

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Answer = 5 (OPTION C)

First we need to find the 17 combinations which would be there:
They would be 5,10,15,20,25,30,35...........till n=17
N(17)= 5 + (17-1)5
N(17)= 5 + 80 = 85

now we know that 85 is the 17th unique combination made of 5's and 10's
Thus 85=5x+10y ---------------1
we also know x+y=12 ------------2

By solving the two equations we get
y=5
x=7
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Just one doubt in this: Why only multiples of 5 is being considered?
Fdambro294
She has 12 coins: some are 5 cents and some are 10 cents

Any particular combination of a 10 cent coin or a 5 cent coin will always give us a multiple of 5.

Because we are allowed to make every unique combination of coins that is possible, it should be the case that we can make every multiple of 5 within the following range ————->

From 1 coin of 5 cents


To choosing all 12 coins to get the maximum SUM

We are told there are 17 unique totals that can be made.


The first 17 multiples of 5 are from:

[5 through 85]


The correct amount of 5 cent coins and 10 cent coins should give us a MAX SUM Total of 85 cents when we Choose All 12 coins

every other multiple of 5 prior to 85 will be able to be made as a SUM through choosing some combination of 5 cent and 10 cent coins

Thus, we are looking for which combination of 12 coins will give us a MAX total of 85 cents when we choose all 12 of them and add them up?

(C) Ten cent coins = 5

Which means Five cent coins = 7

If we choose all 12 coins, the MAX SUM total will be:

(5 coins) (10 cents) + (7 coins) (5 cents) =

50 + 35 = 85 cents

This is the amount we would get on our 17th final unique combination when we choose all the coins. we can not create any higher SUM and we should be able to create every other Multiple of 5 prior to 85 by choosing some combination of Five Cent and Ten Cent coins.

This will result in 17 possible Unique Sums: 5, 10, 15......... all the way to MAX 85


Thus,

(C) 5

Posted from my mobile device
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Hi Rohan271,

Given that the coins are either 5 cent or 10 cent, the possible values obtained by addition can only be multiples of 5. For instance, can any combination of 5-cent and/or 10 cent coins give us a value of 17? Mathematically not possible.

Above is a simpler example to understand what is happening.

For this question

Let the number of 10 cent coins be x. Then, the number of 5 cent coins = 12 - x.

Now, we are given that there are 17 unique values that can be reached by taking various combinations of one or more coins.

These values are: 5, 10, 15, 20,...............(max possible value i.e., counting all coins)
In other words: 5, 10, 15, 20,....... 10x + 5 (12-x)

5, 10, 15,..............60 + 5x

We are given that the number of terms of the above = 17.

60 + 5x = 5 + (17-1)5
=> x = 5.

Thus, the number of 10-cent coins = 5.

Hope this helps!
Harsha
Rohan271
Just one doubt in this: Why only multiples of 5 is being considered?
Fdambro294
She has 12 coins: some are 5 cents and some are 10 cents

Any particular combination of a 10 cent coin or a 5 cent coin will always give us a multiple of 5.

Because we are allowed to make every unique combination of coins that is possible, it should be the case that we can make every multiple of 5 within the following range ————->

From 1 coin of 5 cents


To choosing all 12 coins to get the maximum SUM

We are told there are 17 unique totals that can be made.


The first 17 multiples of 5 are from:

[5 through 85]


The correct amount of 5 cent coins and 10 cent coins should give us a MAX SUM Total of 85 cents when we Choose All 12 coins

every other multiple of 5 prior to 85 will be able to be made as a SUM through choosing some combination of 5 cent and 10 cent coins

Thus, we are looking for which combination of 12 coins will give us a MAX total of 85 cents when we choose all 12 of them and add them up?

(C) Ten cent coins = 5

Which means Five cent coins = 7

If we choose all 12 coins, the MAX SUM total will be:

(5 coins) (10 cents) + (7 coins) (5 cents) =

50 + 35 = 85 cents

This is the amount we would get on our 17th final unique combination when we choose all the coins. we can not create any higher SUM and we should be able to create every other Multiple of 5 prior to 85 by choosing some combination of Five Cent and Ten Cent coins.

This will result in 17 possible Unique Sums: 5, 10, 15......... all the way to MAX 85


Thus,

(C) 5

Posted from my mobile device
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