ManjariMishra
She has 12 coins.
We can obtain 17 distinct values with the 12 coins i.e. 17 distinct sums of money with the 12 coins.
If all 12 coins were 5 cent coins, we could have obtained a total of 60 cents in multiples of 5 i.e. 5 cents, 10 cents, 15 cents, 20 cents, ... 55 cents, 60 cents. These are just 12 distinct sums of money.
If all 12 coins were 10 cent coins, we could have obtained a total of 120 cents in multiples of 10 i.e. 10 cents, 20 cents, 30 cents, 40 cents, ... 110 cents, 120 cents. These are just 12 distinct sums of money.
To get 17 combinations, we must have a mix of 5 cent and 10 cent coins.
Now note that you can make each multiple of 5 till the max multiple of 5 as per the number of coins.
Say of the 12 coins, 10 are 5 cent coins and 2 are 10 cent coins.
Max amount = 10*5 + 2*10 = 70 cents
5c, 10c, 15c (a 10c and a 5c), 20c (2 10c coins), ... for all other sums, just keep adding 5.
Similarly, if we have 17 distinct sums, it means the maximum amount is 85 cents (so 17 distinct sums will be 5c, 10c, 15c ... 85c)
So, if x is the number of 5 cent coins and y is the number of 10 cent coins,
x + y = 12
5x + 10y = 85
Solve to get x = 7 and y = 5
Answer (C)Method 2:Use the options. Since number of 10 cent coins must be between 3 to 7, there are a mix of both type of coins. So this means we can make every multiple of 5 with the coins we have till the sum of all the coins together.
Say even if we had only one coin of 5 cent, we would be able to make 5, 10, 15, 20, 25, 30, 35.... etc all.
So let's look at the options to see what gives us 17 combinations. I tried (C) first because it is right in the middle. It will tell me whether to go up or down.
5 cent coins - 7
10 cent coins - 5
Total value = 5*7 + 10*5 = 85 = 5 * 17
So here we have 17 distinct values: 5, 10, 15, 20, 25, ... 85
Answer (C)Had we got more than 17 values here, we would have tried 3 or 4 and would have got our answer either way.
Had we got fewer than 17 values here, we would have tried 6 or 7 and would have got our answer either way.