Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized for You
we will pick new questions that match your level based on your Timer History
Track Your Progress
every week, we’ll send you an estimated GMAT score based on your performance
Practice Pays
we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:
Hello everyone, could you please help me with solving the below 2 question?
A machine has 4 components A, B, C and D. The raw material is the input to the component A; if the component A works, its output automatically becomes the input to the component B; again if the component B works, its output becomes the input to the component C; if the component C works, its output becomes the input to the component D; finally if the component D works, its output is the final product. If at any stage, the component under consideration fails, we say that the machine fails. The component A fails 1% of the times. Given that A works, B fails 2% of the times. Given that A and B work, C fails 3% of the times. Finally, given that A, B and C work, D fails 4% of the times.
1. What is the probability that the machine fails?
a. 0.1
b. 0.09244976
c. 0.09654976
d. 0.09564046
2. Given that the machine fails, what is the probability (correct to 6 places of decimal) that it fails
at the third stage (that is C fails when its turn comes)?
a. 0.301461
b. 0.029106
c. 0.030001
d. None of the above
Still interested in this question? Check out the "Best Topics" block below for a better discussion on this exact question, as well as several more related questions.
1. Probability that the machine fails = (A fails) OR (A works, but B fails) OR (A and B work, but C fails) OR (A, B, and C work, but D fails) = 0.01 + 0.99 * 0.02 + 0.99 * 0.98 * 0.03 + 0.99*0.98*0.97*0.04 = 0.09654976 Option (C).
2. Probability that the machine fails at the third stage = A and B work, but C fails = 0.99 * 0.98 * 0.03 = 0.029106 Option (B)
Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.