Is y

Question

Is y < z ?

(1) y + z = 1

(2) y^2 < z^2

GeorgeKo111 · Answer

SOLUTION

Choice (C) is correct.

The stem doesn't give us much information to work with, so we can go directly to the statements. They will be sufficient only if y must be less than z or cannot be less than z.

Statement (1): insufficient. This tells us the sum of y and z, but it says nothing about their relative values. It is possible that y and z are equal (if each is 0.5), or that either variable is greater (e.g., y = 1 and z = 0, or vice versa). Eliminate (A) and (D).

Statement (2): insufficient. Let's say that y2 = 9 and that z2 = 25. Then y = 3 or -3 and z = 5 or -5. If y = 3 and z = 5, then z is greater. However, if y = -3 and z = -5, then y is greater. The question cannot be answered definitively, so the statement is insufficient. Eliminate (B).

Statements (1) and (2): sufficient. Picking numbers may be difficult, since there are many possibilities for y and z. Instead, try to work with the equations. Since y + z = 1, it follows that y = 1 - z. Replace y with 1 - z in the equation y2 < z2 to get (1 - z)2 < z2. Using FOIL to expand the left side, you get z2 - 2z + 1 < z2. Subtracting z2 from both sides you have -2z + 1 < 0, or 1 < 2z. Dividing both sides by 2 you are left with < z. Since z must be greater than and y + z = 1, y must be less than . Therefore, y must be less than z. The statements combined are sufficient, so choice (C) is correct.

BrentGMATPrepNow · Answer

Target question :    Is y < z ?

Statement 1 : y + z = 1  
Let's TEST some values.
There are several values of y and z that satisfy statement 1. Here are two: 
 Case a : y = 0 and z = 1. In this case, the answer to the target question is  YES, y is less than z 
 Case b : y = 1 and z = 0. In this case, the answer to the target question is  NO, y is not less than z 
Since we cannot answer the  target question  with certainty, statement 1 is NOT SUFFICIENT

Statement 2 : y² < z² 
There are several values of y and z that satisfy statement 2. Here are two: 
 Case a : y = 0 and z = 1. In this case, the answer to the target question is  YES, y is less than z 
 Case b : y = 0 and z = -1. In this case, the answer to the target question is  NO, y is not less than z 
Since we cannot answer the  target question  with certainty, statement 2 is NOT SUFFICIENT

Statements 1 and 2 combined    
Statement 2 tells us that: y² < z²
Subtract z² from both sides of the inequality to get: y² - z² < 0
Factor the left side to get: (y + z)(y - z) < 0
Since statement 1 tells us that y + z = 1, we can replace (y + z) with 1 to get: (1)(y - z) < 0
Simplify: y - z < 0
Add z to both sides to get:  y < z 
The answer to the target question is  YES, y is less than z 
Since we can answer the  target question  with certainty, the combined statements are SUFFICIENT

Answer: C

Cheers,
Brent

RELATED VIDEO 
 https://www.youtube.com/watch?v=Od98BOicIq4

akshitab2912 · Answer

Hi Brent,

Can't we answer the question from statement 2 itself?

y^2-z^2<0 
(y+z)(y-z)<0
-z<y<z
So y in any case is less than z from second statement itself, isn't that so?

QuantMadeEasy · Answer

Step 1: Understanding statement 1 alone (1) y + z = 1 When y = 0.4, z = 0.6; y < z When y = 0.6, x = 0.4; y > z Insufficient Step 2: Understanding statement 2 alone (2) y^2 < z^2 Taking square root on both the sides \sqrt{y^2} < \sqrt{z^2} |y| < |z| When y = -1, z = 2; y < z When y = 1, z = -2; y > z Insufficient Step 3: Combining statement 1 and 2 y^2 < z^2 y^2 - z^2 < 0 (y - z) ( y+z) < 0 As (y + z) = 1; (y - z) < 0 Hence, y < z Sufficient C is correct

GMATGuruNY · Answer

Alternate approach: Statement 1: Clearly INSUFFICIENT. Statement 2, rephrased: |y| < |z| Case 1: y=0 and z=1 In this case, the answer to the question stem is YES. Case 2: y=0 and z=-1 In this case, the answer to the question stem is NO. Since the answer is YES in Case 1 but NO in Case 2, INSUFFICIENT. Statements combined: Substituting z=1-y into |y| < |z|, we get: |y| < |1-y| Implication: The distance between y and 0 is less than the distance between y and 1. In other words, Y IS CLOSER TO 0 THAN TO 1, implying that y < 1/2. Substituting y=1-z into |y| < |z|, we get: |1-z| < |z| Implication: The distance between z and 1 is less than the distance between z and 0. In other words, Z IS CLOSER TO 1 THAN TO 0, implying that z > 1/2. Since y < 1/2 and z > 1/2, we get: y < 1/2 < z y < z Thus, the answer to the question stem is YES. SUFFICIENT. C

Saransh123 · Answer

I have solved this problem like this
Statement 1 says y+z=1, y=1-z or z=1-y Not Sufficient at all.

Statement 2 says y^2 < z^2

Putting value of y(1-z) in y^2<z^2 = 1-2z+z^2, 1/2<z

Similarly putting value of Z(z=1-y) in y^2<z^2, the result will be y<1/2.

So now after joining them it will give y<1/2<z. Therefore the statements combined are sufficient.

Posted from my mobile device

IanStewart · Answer

We want to know if z-y is positive. Statement 1 tells us that z+y is positive, and Statement 2 tells us that z^2 - y^2 is positive. But z^2 - y^2 = (z + y)(z-y), and if z+y is positive, then z-y must also be positive for it to be true that the product (z-y)(z+y) is positive. So the two Statements together are sufficient.

Statement 1 is clearly insufficient alone, because it's symmetric in y and z (if you can find numbers that work for y and z where y < z, you can just flip the numbers and you'll automatically have a situation where z < y). Statement 2 is clearly insufficient alone also, since if y = 0, z can be -100 or +100. So the answer is C.

Basshead · Answer

Is  y < z  ?

(1)  y + z = 1
 
Clearly insufficient.

(2)  y^2 < z^2

y^2 - x^2 < 0 
 (y+z)(y-z) < 0

(y+z) and (y-z)  have different signs. We can't conclude y <z, however. INSUFFICIENT.

(1&2)
If  y+z = 1, then y-z < 0 
 y < z .

SUFFICIENT.

Answer is C.

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Is y < z ? (1) y + z = 1 (2) y^2 < z^2

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