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Bunuel
What is the product of the roots of the equation \(y = |x|^2 - 5|x| + 6\)?

(A) -36
(B) 6
(C) -6
(D) 36
(E) 0

Find the product of the roots of the equation \(y = |x|^2 - 5|x| + 6\), where |x| is the modulus of x.

Trick is to realize that |x|^2 will always be positive irrespective of the sign of x.
If x<0 then |x|=-x but |x|^2=(-x)^2=x^2
If x>=0 then |x|=x and |x|^2=x^2

So the equation can be converted to y=x^2 -5|x| +6
Then solve for the roots as 3,2 and -3,-2
Product of roots = 36
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Bunuel
What is the product of the roots of the equation \(y = |x|^2 - 5|x| + 6\)?

(A) -36
(B) 6
(C) -6
(D) 36
(E) 0


Are You Up For the Challenge: 700 Level Questions

Find the product of the roots of the equation \(y = |x|^2 - 5|x| + 6\), where |x| is the modulus of x.
Treat \(y = |x|^2 - 5|x| + 6\) as \(y = x^2 - 5x + 6\)

Or, \(y = x^2 -3x - 2x + 6\)

Or, \(y = x(x -3) - 2( x - 3)\)

Or, \(y = (x -3)(x - 2)\)

Now if \(y = 0\) we have \(x = 3 , 2\)

Now, initially we have assumed only the +ve values of \(y\), as \(3 , 2\), so the other possible values are \(-3 , -2\)

Thus, the product will be \(3*2*-3*-2 = 36\), Hence Answer must be (D)
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We need to find the product of the roots of the equation \(y = |x|^2 - 5|x| + 6\)?

\(y = |x|^2 - 5|x| + 6\)
=> \(y = x^2 - 5|x| + 6\) (|x|^2 is same as x^2, both are non-negative)

As we have |x| in the equation so we will have two cases
-Case 1: x ≥ 0

=> |x| = x
=> \(x^2 – 5x + 6 = 0\)
=> \(x^2 -2x -3x + 6 = 0\)
=> x*(x - 2) - 3*(x - 2) = 0
=> (x - 2) * (x - 3) = 0
=> x = 2, 3

But condition was x ≥ 0 and both 2 and 3 are ≥ 0
=> x = 2, 3 are SOLUTIONS
-Case 2: x ≤ 0

=> |x| = -x
=> \( x^2 + 5x + 6 = 0 \)
=> \(x^2 + 2x + 3x + 6 = 0\)
=> x*(x + 2) + 3*(x + 2) = 0
=> (x + 2) * (x + 3) = 0
=> x = -2, -3

But condition was x ≤ 0 and both -2 and -3 are ≤ 0
=> x = -2, -3 are SOLUTIONS

So, Product of the roots = 2 * 3 * -2 * -3 = 36

So, Answer will be D
Hope it helps!

Watch the following video to learn the Basics of Absolute Values

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pardhu1212
When the equation is in the form of \(y=ax^2+bx+c\), the product of the roots of the equation is \(\frac{c}{a}\).

The equation in the question can be split into two different equations \(x^2-5x+6\) and \(x^2+5x+6\) when \(x>6\) and \(x<6\) respectively.

The final answer is the product of the products of roots of these two equations. In each equation, the product is \(6/1=6\). Hence the final answer is 36.


This is the easiest.
Product of the roots, c/a
In this case 6/1 and 6/1
answer is 36: D
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I solved this by using P.O.R=C/A, c=36, since |x|^2 is given, a is always 1 , so POR=36. Am I wrong here?
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