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2018 is closest to \(45^2 = 2025\)

Dividing Each term in the Numerator and denominator by 2018, we get


\(\frac{\frac{2018(\sqrt{2018})}{2018} - \frac{1}{2018}}{\frac{2018}{2018} + \frac{\sqrt{2018}}{2018} + \frac{1}{2018}}\)


\(\frac{1}{2018}\) is very small and can be igniored. Similarly, \(\frac{\sqrt{2018}}{2018} = \frac{1}{\sqrt{2018}} = \frac{1}{45} \approx \frac{1}{50} = 0.02\) and this too can be ignored.


Therefore the following expression becomes \(\frac{\sqrt{2018} - 1}{1 + 0 + 0} \approx 45 - 1 \approx 44\)


Option E

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Ok after seeing the solution I feel so dumb that I couldn't figure it was a a3-b3 expression !!((
But this is the way I tackled it while solving.
(2018√2018)−1
2018+(√2018)+1

I neglected both 1's in numerator and denominator since they were small compared to the other numbers. XD
eq became:
(2018√2018)
2018+(√2018)

(2018√2018)
(√2018)(√2018 +1)

then canceled out √2018 on top and down
remaining was:
2018
1+(√2018)

then again neglected the 1.
so eq became

2018
√2018

finally arrived to √2018 ~ 44­
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Does anyone have a quick way to find the root of 2018? Spent a lot of time trying the numbers....­
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zxl2945
Does anyone have a quick way to find the root of 2018? Spent a lot of time trying the numbers....­

­40^2 = 1,600
50^2 = 2,500

So, √2,018 should be close to 45^2. Let's still check: 45^2 = (40 + 5)^2 = 1,600 + 400 + 25 = 2,025, which is close enough.
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