For some reason I’ve been seeing a few times of these types of questions. Not sure whether it makes sense to memorize the formula or not.
P ———————Meet———————Q
A leaves P——->. <————-B leaves Q
Let speed of A = A
Let speed of B = B
(1st)
From point P to Meet: (Speed of A) * (Time it takes to Meet) = AT
From point Q to Meet: (Speed of B) * (Time it takes to Meet) = BT
So:
AT = Meet to P
BT = Meet to Q
(2nd)
Then it takes A 54 minutes or 9/10 of an hour to go from Meet to Q
(9/10)A = Meet to Q
And it takes B 24 minutes or 2/5 of an hour to go from Meet to P
(2/5)B = Meet to P
Set up a proportion:
Meet to P / Meet to Q
AT / BT = (2B/5) / (9A/10)
-cancel T and cross multiply A and B
(A)^2 / (B)^2 = (2/5) / (9/10) = 20 / 45 = 4/9
Take the square root of both sides (A and an are positive values since they are speeds)
A/B = 2/3
Ratio of Speeds: A : B = 2 : 3
Over the same distance, the Ratio of Times taken will be inversely proportional:
Ratio of Times: a : b = 3x : 2x
It takes A a Time of: a = 54 minutes to travel from the Meet Point to Point Q
3x= 54 ——-> x = 18
Thus it will take B: 2x = 2(18) = 36 minutes to travel from Point Q to Meet Point
Then it takes B another 24 minutes to get to Point P
Total Time for B = 36 + 24 = 60 minutes or 1 hour
A
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