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kawal27
Using the letters from the word ‘TRAPEZIUM’, how many combinations 5 letters can be formed such that they have exactly 3 consonants?



A)120

B)600

C)3,600

D)4,800

E)7,200


need detail explanation

There are 5 Places -

_ _ _ _ _

1. There are 5 Consonents T, R , P , Z & M
2. There are 4 Consonents A , E , I, U
3. Total there are 9 letters

3 Consonents can be chosen in \(5C_3\) ways , and the next 2 letters can be chosen in \(4C_2\) ways

Further the arrangement of the letters can be done in 5! ways, so total no of ways possible is 5!*\(5C_3\)*\(4C_2\) = 7,200 ways, Answer must be (E)

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