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02 Mar 2021, 06:45
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
45%
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Question Stats:
65% (01:43) correct
35%
(02:11)
wrong
based on 186
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In how many ways can 4 different consonants and 3 different vowels be arranged in a row so that the first and the last places are occupied by consonants ?
A. 360
B. 720
C. 900
D. 1080
E. 1440
A. 360
B. 720
C. 900
D. 1080
E. 1440
02 Mar 2021, 06:57
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There are 7 letters in total. Since we have a restriction, we satisfy the same first.
We can pick and arrange 2 consonants out of 4 in 4C2 * 2! = 4P2 = 12 ways
The remaining 5 letters can be arranged in 5! = 120 ways
The total arrangements = 12 * 120 = 1440
Option E
Arun Kumar
We can pick and arrange 2 consonants out of 4 in 4C2 * 2! = 4P2 = 12 ways
The remaining 5 letters can be arranged in 5! = 120 ways
The total arrangements = 12 * 120 = 1440
Option E
Arun Kumar
30 Dec 2023, 11:25
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CrackverbalGMAT
What gave you the que you needed to deduce that all consonants aren't the same? I.e. why do we have to pick and arrange consonants if we do not know if they are the same or not? For all we know, all consonants could be the same letter.
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