Bunuel
Michelle deposited a certain sum of money in a savings account on July 1st, 2007. She earns an 8% interest compounded semiannually. The sum of money in the account on December 31st, 2009 is approximately what percent of the initial deposit?
A. 117%
B. 120%
C. 121%
D. 135%
E. 140%
Formula for compound interest:
Final value = initial value * \((1 + \frac{p}{c})^{t*c}\), where p = yearly interest, c = number of payments per year, t = number of years
Let's Test it using a simple initial value.
Let the initial value be 100.
p = 8% = \(\frac{8}{100}\)
c = 2 (semianually = twice per year)
t would be a fraction, but let's view it this way:
July - Dec. 2007: 1 payment
2008: 2 payments
2009: 2 payments
Total: 5 payments --> t*c = 5
Let's plug it into the equation:
Final value = \(100 * (1 + \frac{8}{2*100})^{5}\) = \(100 * (1 + \frac{4}{100})^{5}\) = \(100 * 1.04^5\)
After 1st payment: 100 * 1,04 = 104
After 2nd payment: 104 * 1,04 \(\approx\) 108
After 3rd payment: 108 * 1,04 \(\approx\) 112
After 4th payment: 112 * 1,04 \(\approx\) 116
After 5th payment: 116 * 1,04 \(\approx\) 120
Since we added 4 after each payment, we "ignored" the values after decimal due to simplification.
Therefore, the final value needs to be a bit bigger than 120.
The answer that fits best is
Answer C: 121%Does anyone have a better way to handle such percent-values with exponents?
I think I lost some valuable time in this step. There must be an easier way.
Thank you in advance!!
Kudos are appreciated