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Hi Bunuel,

I have a question.
As per the given solution, any value except number "1" should satisfy the equation. So, B i.e. x>1 must be true right?
Please tell me, what am I missing here because in this case we have two answers which seem correct : B and E.
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Hi Bunuel,

I have a question.
As per the given solution, any value except number "1" should satisfy the equation. So, B i.e. x>1 must be true right?
Please tell me, what am I missing here because in this case we have two answers which seem correct : B and E.

The question asks: "which of the following must be true?" x > 1 is not necessarily true because x could be any number less than 1, for example, 1/2, or -1000...
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Asked: If |5x - 5| > x - 1, which of the following must be true?

Case 1: x >= 1
5x - 5 > x - 1
4x > 4
x > 1
x = 1 is not possible since 0 > 0 does not hold true

Case 2: x<1
5 - 5x > x - 1
6x < 6
x < 1

Combining
|5x - 5| > x - 1 holds true for all x but 1.

IMO E
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Bunuel
If |5x - 5| > x - 1, which of the following must be true?

A slightly different solution to Bunuel's: |5x - 5| = 5|x - 1|. Unless x= 1, |x - 1| is positive, in which case 5|x - 1| > |x - 1| (if you multiply a positive number by 5, it gets bigger), and naturally |x - 1| > x- 1. Putting those two inequalities together, if x isn't equal to one, 5|x - 1| > x - 1, and |5x - 5| > x - 1. So the inequality is true for every value of x except x= 1, and the answer is E.
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Kinshook

Case 2: x<1
5 - 5x > x - 1
6x > 6
x > 1
Not feasible

x > 1

IMO B

The line I highlighted in red above should read "6 > 6x", so you should reach the conclusion that "x < 1" in this case.
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