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Bunuel
Evaluate: 6^2 + 7^2 + 8^2 + 9^2 + 10^2 + 11^2

(A) 449
(B) 450
(C) 451
(D) 452
(E) 453

Sum(n^2) = [n(n+1)(2n+1)] / 6

Approach: Find sum of squares of first 11 natural numbers, and subtract from sum of squares of first 5 natural numbers.

Sum (11) - Sum (5)
= [11(11+1)(2*11+1)] / 6 - [5(5+1)(2*5+1)] / 6
= [11(2)(23)] - [5(11)]
= [11*46] - 55
= 506 - 55
= 451

Option C

P.S. Might not be the shortest possible path, but knowing this approach can be beneficial for other questions.
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The shortest way is to look at the options and observe the units digit are different for all options :

Hence just add the units digit of the expression:

Units digit for 6^2, 7^2, 8^2, 9^2, 10^2 and 11^2 are 6,9,4,1,0,1 if u add them units digit will come out to be 1

Answer should be C : 451, only answer that has 1 at unit’s place.

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