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bv8562
25^5* 4^6 = 10^x + a
(5^2)^5 * (2^2)^6 = 10^x + a
5^10 * 2^12 = 10^x + a
4 * 10^10 = 10^x + a

x = 10 then minimum positive value of 'a' can be 3*10^10 (E) IMO
Can you explain pls how did you get
5^10 * 2^12 => 4 *10^10?
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bv8562
25^5* 4^6 = 10^x + a
(5^2)^5 * (2^2)^6 = 10^x + a
5^10 * 2^12 = 10^x + a
4 * 10^10 = 10^x + a

x = 10 then minimum positive value of 'a' can be 3*10^10 (E) IMO
Can you explain pls how did you get
5^10 * 2^12 => 4 *10^10?

5^10 * 2^12 = 10^x + a

To make 10 we need a combination of 2 and 5. Since, there are Ten 5's and Twelve 2's, the maximum no. of 10's we can make is (2*5)^10. Then, we will be left with Two 2's, which gives us the following equation:

2^2 * (2*5)^10 = 10^x + a

4 * 10^10 = 10^x + a
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Asked: If \(25^5*4^6 = 10^x + a\), and x is an integer, what could be the minimum positive value of a?

\(25^5*4^6 = 5^10*2^12 = 10^10*2^2 = 4*10^10 = 10^10 + 3*10^10 = 10^x + a\)

a = 3*10^10 = 30,000,000,000

IMO E
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