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Given: A state has 20 cities. The train service in the state connects all cities in triplets; this means that one train shall circulate only among three particular cities.

Asked: To ensure that any set of three cities in the state is interconnected through a triplet, what is the minimum number of trains needed?

Minimum number of trains needed = 20C3 = 1140

IMO C
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magic73
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This question can be easily solved by using the concept of Combination
The minimum number of trains needed is same as no of ways you can select 3 cities out of 20 = 20 C 3 = (20* 19* 18)/3! = (20* 19* 18)/6= 20 * 19 * 3 = 1140

Option C is the correct answer.

Thanks,
Clifin J Francis,
GMAT SME

I don't think C is correct. It should not be a combination. Consider the case with 4 cities instead of 20. 4c3 equals 4. However, you can cover 4 cities using just 3 triplets - ABC, BCD and ACD. Similarly, 6 cities can be covered in less than 6C3 (I have found a solution where 6 cities can be covered in 6 triplets).

Posted from my mobile device

ExpertsGlobal , please help here!
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Could someone please explain the underlying concept? How does the combination of 3 out of 20 ensure all stations would be covered?
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magic73
CrackverbalGMAT
This question can be easily solved by using the concept of Combination
The minimum number of trains needed is same as no of ways you can select 3 cities out of 20 = 20 C 3 = (20* 19* 18)/3! = (20* 19* 18)/6= 20 * 19 * 3 = 1140

Option C is the correct answer.

Thanks,
Clifin J Francis,
GMAT SME

I don't think C is correct. It should not be a combination. Consider the case with 4 cities instead of 20. 4c3 equals 4. However, you can cover 4 cities using just 3 triplets - ABC, BCD and ACD. Similarly, 6 cities can be covered in less than 6C3 (I have found a solution where 6 cities can be covered in 6 triplets).

Posted from my mobile device

C is correct. If you apply 4c3 for 4 cities, ABCD the answer is 4 - ABC, ABD, ACD, and BCD.
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Could someone please explain the underlying concept? How does the combination of 3 out of 20 ensure all stations would be covered?

ThomasK, good question. Before solving, I believe the experts should highlight their reasons to help others understand the solution set better. I am no expert, but I shall try my best.

To ensure that any set of three cities in the state is interconnected through a triplet, what is the minimum number of trains needed

The above statement hints towards using Combinations. Why? Because we need to find ALL the possible ways in which three out of the 20 cities can be connected. All the possible connections = Minimum number of trains needed (If you still do not understand why the above translates to combinations, revise the concepts of Combinations. Once you do, revisit this question)


So, the question basically says "In how many ways can you select 3 out of 20," i.e. 20C3

Answer: (C)
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magic73
CrackverbalGMAT
This question can be easily solved by using the concept of Combination
The minimum number of trains needed is same as no of ways you can select 3 cities out of 20 = 20 C 3 = (20* 19* 18)/3! = (20* 19* 18)/6= 20 * 19 * 3 = 1140

Option C is the correct answer.

Thanks,
Clifin J Francis,
GMAT SME

I don't think C is correct. It should not be a combination. Consider the case with 4 cities instead of 20. 4c3 equals 4. However, you can cover 4 cities using just 3 triplets - ABC, BCD and ACD. Similarly, 6 cities can be covered in less than 6C3 (I have found a solution where 6 cities can be covered in 6 triplets).

The fourth case is "ABD".
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Bunuel
A state has 20 cities. The train service in the state connects all cities in triplets; this means that one train shall circulate only among three particular cities. To ensure that any set of three cities in the state is interconnected through a triplet, what is the minimum number of trains needed?

A. 6840
B. 2280
C. 1140
D. 570
E. 60


In the question we require selection. Out of the 20 cities, we need EVERY group of 3 cities that we can make since we want a train to connect ANY set of 3 cities.
So 20C3 will give us the number of groups of 3 cities we can make out of 20 cities.

For each such group, we will need 1 train.

Hence, 20C3 = 20*19*18/3*2*1 = 1140

Answer (C)

Check this video for an explanation of when to use combinations: https://youtu.be/tUPJhcUxllQ
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