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hadiyahboukhari
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Don intended to place a mark 2 1/4 inches from one end of a Updated on: 03 Oct 2021, 01:02
Originally posted by hadiyahboukhari on 02 Oct 2021, 11:46.
Last edited by Bunuel on 03 Oct 2021, 01:02, edited 4 times in total.
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Question Stats:

72% (01:38) correct 28% (01:19) wrong based on 32 sessions

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Don intended to place a mark 2 1/4 inches from one end of a narrow end 9 1/4 inches long, but he mistakenly placed the mark 2 1/4 inches from the other end. How far, in inches, is his mark from the location where he intended to place it?

A. 4 ½
B. 4 ¾
C. 5 ¾
D. 5 ¼
E. 6 ¾

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Don intended to place a mark 2 1/4 inches from one end of a 02 Oct 2021, 11:52
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Moving to the Quant sub-forum.

Can you please also include the answer choices?

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hadiyahboukhari
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Don intended to place a mark 2 1/4 inches from one end of a 02 Oct 2021, 12:22
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Moving to the Quant sub-forum.

Can you please also include the answer choices?

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yes i'm sorry. I just edited it again.
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Don intended to place a mark 2 1/4 inches from one end of a 02 Oct 2021, 13:43
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hadiyahboukhari
Don intended to place a mark 2 1/4 inches from one end of a narrow end 9 1/4 inches long, but he mistakenly placed the mark 2 1/4 inches from the other end. How far, in inches, is his mark from the location where he intended to place it?
A. 4 ½
B. 4 ¾
C. 5 ¾
D. 5 ¼
Show more
Hello, hadiyahboukhari. Are you going to add an OA at some point? Also, I am not sure what a "narrow end" may be—a narrow piece of wood, perhaps?—and the four answer choices make this question a little different in flavor from a GMAT™ PS question, but I will give it a go anyway. I drew a picture on my board that resembles the following:

2.25 |--------7--------- = 9.25
------|--------------|2.25

If the mark was drawn 2.25 inches from, say, the left end, then 7 inches remained to right. If the mark was supposed to have been drawn 2.25 inches from the right end, we just need to cover the distance within the 7 inches between the two marks.

\(7-2.25=4.75\)

The answer should be (B).

Alternatively, we could simply subtract the 2.25 inches from both ends of the total length:

\(9.25 - 2(2.25)\)

\(9.25 - 4.50=4.75\)

Either way, we arrive at the same answer.

I am not sure where you may have come across this question, but whatever the source, thank you for sharing.

- Andrew
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Don intended to place a mark 2 1/4 inches from one end of a 02 Oct 2021, 14:21
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hadiyahboukhari
Don intended to place a mark 2 1/4 inches from one end of a narrow end 9 1/4 inches long, but he mistakenly placed the mark 2 1/4 inches from the other end. How far, in inches, is his mark from the location where he intended to place it?
A. 4 ½
B. 4 ¾
C. 5 ¾
D. 5 ¼
Hello, hadiyahboukhari. Are you going to add an OA at some point? Also, I am not sure what a "narrow end" may be—a narrow piece of wood, perhaps?—and the four answer choices make this question a little different in flavor from a GMAT™ PS question, but I will give it a go anyway. I drew a picture on my board that resembles the following:

2.25 |--------7--------- = 9.25
------|--------------|2.25

If the mark was drawn 2.25 inches from, say, the left end, then 7 inches remained to right. If the mark was supposed to have been drawn 2.25 inches from the right end, we just need to cover the distance within the 7 inches between the two marks.

\(7-2.25=4.75\)

The answer should be (B).

Alternatively, we could simply subtract the 2.25 inches from both ends of the total length:

\(9.25 - 2(2.25)\)

\(9.25 - 4.50=4.75\)

Either way, we arrive at the same answer.

I am not sure where you may have come across this question, but whatever the source, thank you for sharing.

- Andrew
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thanks very much for your answer . thes correct . but i didn't get the second method . tho guess thes okay.. ill be sick to the first one . thanks very much again.
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Don intended to place a mark 2 1/4 inches from one end of a 02 Oct 2021, 21:19
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hadiyahboukhari
Don intended to place a mark 2 1/4 inches from one end of a narrow end 9 1/4 inches long, but he mistakenly placed the mark 2 1/4 inches from the other end. How far, in inches, is his mark from the location where he intended to place it?
A. 4 ½
B. 4 ¾
C. 5 ¾
D. 5 ¼
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The total length of the plank = 37/4

intial marking position = 9/4

The distance between the two marking will give the requisite distance of difference

=> 37/4 -2*9/4
=> 18 /4
=> 4 3/4

Therefore IMO B

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