Rishitha0311
Bunuel
If positive integer X is greater than two, is X the square of an odd prime integer?
(1) X has exactly one composite number as factor.
(2) X has odd number of factors.
Can any of the experts please help with this question? I've opted C as the answer for this.
Thanks in advance!
If positive integer x is greater than two, is x the square of an odd prime integer?The question asks whether x = (odd prime)^2.
(1) x has exactly one composite number as factor.
A composite number is a positive integer greater than 1 that is not prime. x having only one composite factor implies that x itself is that composite factor, meaning x = prime^2 or x = (prime_1)(prime_2).
In the first case, its factors are 1, a prime, and X = prime^2, with X = prime^2 being the only composite factor of X. For example, X can be 2^2 = 4. In this case, its factors are 1, 2, and 4, with 4 being its only composite factor.
In the second case, its factors are 1, (prime_1), (prime_2), and x = (prime_1)(prime_2), with x = (prime_1)(prime_2) being the only composite factor of x. For example, x can be 2*3 = 6. In this case, its factors are 1, 2, 3, and 6, with 6 being its only composite factor.
Hence, from this statement, x can be (odd prime)^2, (even prime)^2, or (prime_1)(prime_2). Not sufficient.
(2) x has odd number of positive factors.
Only the squares of integers have an odd number of positive factors, so this statement implies that x = integer^2. However, we don't know whether that integer is an odd prime or not. Not sufficient.
(1)+(2) Since from (2) we got that x = integer^2, then from (1) we are left with the first case: x = prime^2. However, we still don't know whether x = (odd prime)^2 or x = (even prime)^2. For example, consider x = 9 for a YES answer and x = 4 for a NO answer. Not sufficient.
Answer: E.