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Bunuel
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If a*b*c = 1,536, and a/2 = b/3 = c/4, then c = ? 27 Dec 2021, 07:15
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C
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45% (medium)

Question Stats:

71% (02:37) correct 29% (02:45) wrong based on 180 sessions

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If \(a*b*c = 1,536\), and \(\frac{a}{2} = \frac{b}{3} = \frac{c}{4}\), then \(c = ?\)

(A) 8

(B) 12

(C) 16

(D) 18

(E) 24
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C
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ankitpal10
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If a*b*c = 1,536, and a/2 = b/3 = c/4, then c = ? 29 Dec 2021, 10:24
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a=c/2
b=3c/4

abc=1536
c/2 * 3c/4 * c = 1536

c^3 = 1536*8/3
c = 8 * 2 = 16

ANS (C)
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HenrydeNoble
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If a*b*c = 1,536, and a/2 = b/3 = c/4, then c = ? 14 Aug 2025, 09:19
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Bunuel
If \(a*b*c = 1,536\), and \(\frac{a}{2} = \frac{b}{3} = \frac{c}{4}\), then \(c = ?\)

(A) 8

(B) 12

(C) 16

(D) 18

(E) 24
Show more

Please help me understand.. A * B * C = 1536 so the prime factorization of 1536 should match A, B, & C.

1536 = (2^9)(3)

If A/2 = B/3 = C/4 and there's only one 3 in 1536, shouldn't A = 2, B = 3, and C = 4? But if we only use "one" of the 2's for A, the rest of the 2s or 2^8 would be in C? But that would make the last value 2^7...

What am I missing?
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If a*b*c = 1,536, and a/2 = b/3 = c/4, then c = ? 14 Aug 2025, 09:37
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HenrydeNoble
Bunuel
If \(a*b*c = 1,536\), and \(\frac{a}{2} = \frac{b}{3} = \frac{c}{4}\), then \(c = ?\)

(A) 8

(B) 12

(C) 16

(D) 18

(E) 24

Please help me understand.. A * B * C = 1536 so the prime factorization of 1536 should match A, B, & C.

1536 = (2^9)(3)

If A/2 = B/3 = C/4 and there's only one 3 in 1536, shouldn't A = 2, B = 3, and C = 4? But if we only use "one" of the 2's for A, the rest of the 2s or 2^8 would be in C? But that would make the last value 2^7...

What am I missing?
Show more

Why cannot b also take one of the 2's? For example, consider b = 12.
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sk1999
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If a*b*c = 1,536, and a/2 = b/3 = c/4, then c = ? 14 Aug 2025, 10:29
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If you take one of the ‘2’ for an and rest of the 2s for c then it will not satisfy the condition A/2 = B/3 = C/4.

HenrydeNoble
Bunuel
If \(a*b*c = 1,536\), and \(\frac{a}{2} = \frac{b}{3} = \frac{c}{4}\), then \(c = ?\)

(A) 8

(B) 12

(C) 16

(D) 18

(E) 24

Please help me understand.. A * B * C = 1536 so the prime factorization of 1536 should match A, B, & C.

1536 = (2^9)(3)

If A/2 = B/3 = C/4 and there's only one 3 in 1536, shouldn't A = 2, B = 3, and C = 4? But if we only use "one" of the 2's for A, the rest of the 2s or 2^8 would be in C? But that would make the last value 2^7...

What am I missing?
Show more
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sk1999
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If a*b*c = 1,536, and a/2 = b/3 = c/4, then c = ? 14 Aug 2025, 10:31
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B is in fact equal to 12

Bunuel
HenrydeNoble
Bunuel
If \(a*b*c = 1,536\), and \(\frac{a}{2} = \frac{b}{3} = \frac{c}{4}\), then \(c = ?\)

(A) 8

(B) 12

(C) 16

(D) 18

(E) 24

Please help me understand.. A * B * C = 1536 so the prime factorization of 1536 should match A, B, & C.

1536 = (2^9)(3)

If A/2 = B/3 = C/4 and there's only one 3 in 1536, shouldn't A = 2, B = 3, and C = 4? But if we only use "one" of the 2's for A, the rest of the 2s or 2^8 would be in C? But that would make the last value 2^7...

What am I missing?

Why cannot b also take one of the 2's? For example, consider b = 12.
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