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Question is testing definition of a rhombus.

A rhombus is a special type of square.

A square and therefore a rhombus will have the following:

i) Equal sides
ii) diagonal bisectors that are perpendicular


If either of the two are met then we can be sure it is a rhombus. This now makes the question a lot easier!

1) PQ=QR=RS=SP

Hence all sides are equal. ==> Suff.

2) The line segments SQ and RP are perpendicular bisectors of each other.

Hence opposite sides diagonals are bisectors. ==> Suff.

===> D

Please correct me in understanding if I am wrong.
If both condition are satisfied then we can be sure that given figure is rhombus?
a)PQ=QR=RS=SP -It can be square or rhombus
b)diagonal bisectors that are perpendicular --It can be square or rhombus
I feel both together are not sufficient to answer the question. So it lands to option E
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Charli08
Question is testing definition of a rhombus.

A rhombus is a special type of square.

A square and therefore a rhombus will have the following:

i) Equal sides
ii) diagonal bisectors that are perpendicular


If either of the two are met then we can be sure it is a rhombus. This now makes the question a lot easier!

1) PQ=QR=RS=SP

Hence all sides are equal. ==> Suff.

2) The line segments SQ and RP are perpendicular bisectors of each other.

Hence opposite sides diagonals are bisectors. ==> Suff.

===> D

Please correct me in understanding if I am wrong.
If both condition are satisfied then we can be sure that given figure is rhombus?
a)PQ=QR=RS=SP -It can be square or rhombus
b)diagonal bisectors that are perpendicular --It can be square or rhombus
I feel both together are not sufficient to answer the question. So it lands to option E


No, its an either or situation. So if either one of the two conditions is satisfied then you know its a rhombus/square.

A square is just a special type of square. So every square is always a rhombus too. Hope this helps?
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