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22 Mar 2022, 07:15
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C
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Difficulty:
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Question Stats:
81% (00:54) correct
19%
(01:34)
wrong
based on 171
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What is the probability of rolling a number greater than 2 twice in a row on a fair six-sided die, with each of the numbers 1– 6 on each side?
A. \(\frac{1}{4}\)
B. \(\frac{5}{18}\)
C. \(\frac{4}{9}\)
D. \(\frac{5}{9}\)
E. \(\frac{2}{3}\)
A. \(\frac{1}{4}\)
B. \(\frac{5}{18}\)
C. \(\frac{4}{9}\)
D. \(\frac{5}{9}\)
E. \(\frac{2}{3}\)
29 Mar 2022, 10:07
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Bunuel
Prob = Favorable cases/ total cases
favorable cases :
\(\{3,3\} \{3,4\} \{3,5\} \{3,6\}\)
\(\{4,3\} \{4,4\} \{4,5\} \{4,6\}\)
\(\{5,3\} \{5,4\} \{5,5\} \{5,6\}\)
\(\{6,3\} \{6,4\} \{6,5\} \{6,6\}\)
Favorable cases : \(16 \)
Total cases : \(6*6 =36\)
Probability : \(\frac{16}{36} = \frac{4}{9}\)
Ans C
29 Mar 2022, 10:44
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Each time you roll a die, the probability you get a result greater than '2' is 4/6 = 2/3 (four of the six numbers are greater than 2), so we'll do that twice in a row with probability (2/3)(2/3) = 4/9.
