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HCF x LCM of two numbers = Product of two numbers

The numbers are 4x : 5x

Hence 20x^2 = 800y
So x^2 = 40y | Remember that 40y has to be perfect square
If y = 40, x = 40 and the numbers are 160 and 200 ---> LCM 800 matches
If y = 160, x would be 80 and the numbers would be 320 and 400 the LCM wont be 800

Hence answer is B
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I’m not sure if this is a good way to solve this or not but I find the answer quite fast.
Because the ratio is 4:5 and LCM is 800 so you can just find find the 2 number by 5a=4b=800, and you got a=160 and b=200 and HCF will be 40.
I know this might not work with harder numbers but for these round numbers, I guess it’s quite simple and fast
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Here's the key idea: when two numbers are in a ratio, we can write them using a common multiplier.

Since p : q = 4 : 5, let p = 4k and q = 5k, where k is some positive integer.

Now, note that 4 and 5 share NO common factors (they're coprime). This means the ONLY common factor between 4k and 5k comes from the k part. So the GCD of p and q is simply k.

Next, let's find the LCM. There's a beautiful formula:

LCM × GCD = p × q

Plugging in:
LCM × k = 4k × 5k = 20k2
LCM = 20k

We're told LCM = 800, so:
20k = 800
k = 40

Since GCD = k, the GCD is 40.

Answer: B

Quick verification: p = 4 × 40 = 160, q = 5 × 40 = 200.
- GCD(160, 200) = 40
- LCM(160, 200) = 800

The general principle to remember: If two numbers are in the ratio a : b where a and b are already in simplest form (coprime), then their GCD equals the multiplier k, and their LCM equals a × b × k. This relationship makes ratio + LCM/GCD problems very straightforward.
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