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onlymalapink
does anyone have a better answer' I dont get it.

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­Original ratio for coffee : tea : water is 5 : 6 : 10

In the Afternoon,

i) ratio for coffee : tea triples

\(\frac{5}{6}\) x 3 =\(\frac{15}{6}\)

ii) ratio for coffee : water halves

\(\frac{5}{10}\) x \(\frac{1}{2}\) = \(\frac{5}{20}\)

now, the ratio for coffee : tea : water is 15 : 6 : 60

if we simplify the ratio by dividing everything by 3, we get 5 : 2 : 20
therefore, the minimum number of coffee orders that could have been made in the afternoon is 5.
Answer D

hope this is helpful­
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basically i cant wrap my head around 60 for water
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basically i cant wrap my head around 60 for water
­we have two different ratios which include coffee: 15:6 and 5:20, so to combine all of them into a single ratio, we have to make coffee equal in both the ratios.

we have 2 options, to either simplify the first ratio from 15:6 (dividing by 3) to 5:2 or match the second ratio of 5:20 (multiplying by 3) to get 15:60 where coffee will be same in both the ratios.

i have used the second method which gives me 15:6:60 and then i simplify it by dividing with its HCF.

see that first method directly gives us the answer without the need of further simplifying the ratio - 5:2:20.

hope this is helpful
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Thanks, That makes a whole lot of sense when you mention it.

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Also, as T does not have a multiple of 5, the final answer, the minimum servings of coffee, must be a multiple of 5. Only if we can reduce all three components of a ratio by 5, can it be a different answer. As T never changes, easy to see that the answer must be 5.
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