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18 Oct 2024, 01:30
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A
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85% (01:27) correct
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Students at a school were on average 180 cm tall. The average female height was 170 cm, and the average male height was 184 cms. What was the ratio of men to women?
(A) 5:2
(B) 5:1
(C) 4:3
(D) 4:1
(E) 3:1
(A) 5:2
(B) 5:1
(C) 4:3
(D) 4:1
(E) 3:1
18 Oct 2024, 02:49
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Let's suppose there are "m" number of men & "w" number of women.
So, \(\frac{(170*w+184*m)}{w+m }= 180\)
\(170w+184m = 180w+180m\)
Solving this we get,
\(4m = 10w\)
Asked ratio of men to women:
\(\frac{m}{w} = \frac{10}{4} = \frac{5}{2}\)
I think A.
Hope it helps.
So, \(\frac{(170*w+184*m)}{w+m }= 180\)
\(170w+184m = 180w+180m\)
Solving this we get,
\(4m = 10w\)
Asked ratio of men to women:
\(\frac{m}{w} = \frac{10}{4} = \frac{5}{2}\)
I think A.
Hope it helps.
General Discussion
18 Oct 2024, 01:47
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Male average height \(- 184 cm\)
Female average height \(- 170 cm\)
Overall average height \(- 180cm\)
by weighted average or alligation method,
\(\frac{m}{w}=\frac{180-170}{184-180}=\frac{10}{4}=\frac{5}{2}\)
\(m:w=5:2\)
Answer: A
Female average height \(- 170 cm\)
Overall average height \(- 180cm\)
by weighted average or alligation method,
\(\frac{m}{w}=\frac{180-170}{184-180}=\frac{10}{4}=\frac{5}{2}\)
\(m:w=5:2\)
Answer: A
